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Odd Behavior of Circuit

Discussion in 'General Electronics Discussion' started by ADavis53, Nov 28, 2017.

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  1. BobK

    BobK

    7,682
    1,688
    Jan 5, 2010
    Assuming that those are the leads coming out of the bell, that is not the correct connection for the diode. The diode must be directly across the electromagnet coil in the bell. The way you have it wired, the diode is out of the circuit when the interrupter disconnects the magnet and the EMF pulse is created.

    Bob
     
  2. ADavis53

    ADavis53

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    0
    Nov 17, 2017
    Thanks, Bob. It may be time for me to throw in the towel on this one. I'm not sure i'll be able to install the diode inside the bell itself given my skill set.


    And for Mr. Fixit- Thank you too! I have put the bell on it's own power supply. In all cases i get 12V with no load, 12V with the bell connected and ringing and 12V when the bell stops ringing- i see no variation in voltage under any condition I've tested.

    I spoke to the manufacturer of the timer/relay and he too believes that the bell is generating so much hash that it's causing the timer to constantly reset. He also suggested decoupling the power supply.

    The bell is an old Archer 49-498a.. .i cannot find any documentation on it anywhere. Not surprising given it's 30-40 years old.

    The bell works as intended on its own power supply. rings when it has power, stops as soon as I remove voltage.

    If i give the bell constant power via it's own power supply how can my timer/relay impact when it is supposed to ring? Essentially wire the relay/timer backwards and allow it to complete the (-) leg of the circuit when it's closed?
     
  3. Alec_t

    Alec_t

    2,950
    803
    Jul 7, 2015
    Try connecting a fat cap, say at least 100uF electrolytic (correctly polarised), 25V rated, in parallel with a 100nF ceramic cap, across the bell terminals.
     
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