Gillesfizzog
- Jan 14, 2014
- 18
- Joined
- Jan 14, 2014
- Messages
- 18
I have problem im trying to understand and my teacher here at my college is puzzled aswell, we must be missing something. Here it is.
My goal was to calculate the power factor of a 60 watt light bulb, i think the bulb is an incandescent but the reading im getting with my multimeter makes me think thats there is a coil in it making it an RL circuit. Heres why?
First I tested the voltage at my outlet it was 122 volts.
Then I tested the current that the bulb is drawing and it measured 0.45 amps
Now correct me if im wrong, but from what i learned, in a purely resistive circuit, the bulb should have a resistance of 271 ohms. (122v devided by 0.45 amps)
However, when I test the ohms of the light bulb, it measured 20.5 ohms. For this reason, my teacher thinks its an inductive load.
If it is an inductive load, that means that the calculated power factor would be 7.5% This seems wrong because its such a low efficientcy??? and combine that with the fact that most of the energy used is converted to heat!!! Is this bulb really that inefficient?
My goal was to calculate the power factor of a 60 watt light bulb, i think the bulb is an incandescent but the reading im getting with my multimeter makes me think thats there is a coil in it making it an RL circuit. Heres why?
First I tested the voltage at my outlet it was 122 volts.
Then I tested the current that the bulb is drawing and it measured 0.45 amps
Now correct me if im wrong, but from what i learned, in a purely resistive circuit, the bulb should have a resistance of 271 ohms. (122v devided by 0.45 amps)
However, when I test the ohms of the light bulb, it measured 20.5 ohms. For this reason, my teacher thinks its an inductive load.
If it is an inductive load, that means that the calculated power factor would be 7.5% This seems wrong because its such a low efficientcy??? and combine that with the fact that most of the energy used is converted to heat!!! Is this bulb really that inefficient?