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Newbie with a question: Why do you need those resistors in IC based digital circuits?

Discussion in 'Electronic Basics' started by Steve Wake, Dec 12, 2003.

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  1. Steve Wake

    Steve Wake Guest

    Hi,

    I'm attempting to get into digital circuit design again after a long
    abscencse because I don't like the current 'buy a block box pc with the
    necessary hardware to support what you want' when it looks like you can
    accomplish your goals with small purposed circuits such as the BTnode
    project which fits almost into what I would like to do.

    Anyways, the last time I dabbled in this I always wondered what was meant by
    'pull-up' and 'pull-down' in relation to outputs on an IC. Coming from a
    programmers point of view I look at things like outputting a '1' or a '0',
    meaning whatever the voltage the chip runs at (e.g. 5v or 3.3v) as easy to
    achieve, however suddenly what looks to me like 'analog stuff' such as
    resistors are thrown into the mix as part of the circuit.

    My understanding is that it makes sense that if you output a voltage on a
    pin, such as an address line, during one cycle and then that pin or address
    line is not needed for the next cycle (i.e probably every even address
    access for the lowest pin on a sequential memory access to ram chip) then
    you need to get that pin back to '0' voltage or you'll get the wrong data
    back. Is this what a pull-down resistor does?

    I'm looking at some microcontrollers at the moment which are way more
    integrated than the chips I originally looked at, such as the old MC68000
    series, so maybe the lack of pull-down resistors on every address line is
    because this functionality is integrated on chip? Here is where my confusion
    lies... If that's what they're for then why do you not see them everywhere?

    I do know about latches so is this anything to do with it? Is it a designed
    harmonious combination between two chips which means that one of them is
    doing this internally so you don't need the extra resistor or whatever?

    Thanks,
    Steve
     
  2. John Fields

    John Fields Guest

    ---
    If you look at the outputs of logic devices you will find that there are
    three types; one which is always either at a logic "1" or a logic "0",
    one which is always either at a logic "1" or "0" or floating, (3-state)
    and one which is always either at a logic "0" or floating (open
    collector/open drain).

    Now, if you look at the inputs to CMOS logic devices you will find that
    they are always floating, so that with power applied to the chip and the
    input undefined, the output will always be undefined.

    Now, if you connect the input of a driven logic device to the output of
    a driving logic device which is always pulled up to the positive rail
    ("1") or pulled down to ground ("0") that input will never float and its
    output will always be either a "1" or a "0".

    If you connect the driven input to the output of a 3-state device, then
    the driven device's output will always be defined when the output of the
    3-state device is either a "1" or a "0", but will not be defined when
    the driving device's output goes into the high-impedance 3-state mode.
    The 3-state connection is used when several driving devices' outputs
    need to be connected to the same point, (usually one or more inputs of
    driven devices) and is made to function by turning off all of the
    devices connected to that point but one. In order to keep from having
    two devices' outputs "ON" at the same time, (called "contending for the
    bus") the currently "ON" device is turned "OFF" and then a previously
    "OFF" device is turned on. This results in a sliver of time during
    which the input of the driven device is neither "ON" nor "OFF" and,
    consequently, its output state cannot be defined. In order to keep this
    from happening the bus (the point to which the output devices are
    connected) is either pulled up to a logic "1" with a resistor or pulled
    down to a logic "0" with a resitor in order for the state of the bus
    never to be undefined. This also allows _all_ of the driving devices to
    be turned off, if desired, while leaving the bus in a known state.

    In the case of an open-collector or open-drain output, the (usual)
    output configuration for the driver is that of a transistor with its
    emitter/source grounded and its collector/drain left floating. That way,
    when the output transistor is turned on, the device connected to the
    collector/drain will be switched to ground while when the transistor is
    turned off the device(s) connected to it will be left to float. That
    is, unless the collector is pulled up to a "1", in which case the input
    of the driven device will go to a "1" when the transistor is turned off.

    In the case of the microcontroller you're looking at, there may or may
    not be internal pullups or pulldowns in it, but its documentation will
    surely tell you, and will tell you what you'll need to do to invoke them
    or ignore them if that's what you want to do.
     
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