Alas, the compliance current is around 50mA with a compliance voltage as
high as 1kV, which is destructive. A 'straight' shunt regulator either
shorts out the incoming 50 mA or let's it pass thru, but in this case I
sometimes need 800mA at a small 5Vdc. So, need some 'multiplication' of
the current - a capacitor. There is sufficient power if the system
operates with the compliance at around 80V at 50mA just have to somehow
convert that to 5Vdc at 800mA. But, in this case it will be super
necessary to monitor compliance voltage so it won't EVER go above 100V
in order to NOT kill parts. In this supply that protection circuit, or
'voltage limit', is the corollary of the standard 'current limit' in a
voltage supply!
So far it appears a variation of George Herold's approach may get me
there. the current charges a cap, which then supplies large amount of
power. Aain, corollary, using cap instead of inductor for the energy
storage/conversion.
Hi, Robert -
The thread has grown more to than I can re-read to capture all your
requirements. However, here are my thoughts...
Max allowed input voltage: 100V
Input current capability: 50mA
Output voltage required: 5V
Output current required: .8A
Rather than thinking about this as a current-to-current topology, think
about how much power you can put into the topology within your
constraints. You can't get more power out than your input capability and
limits. But, you know that.
A normal buck switching topology will provide all this. One thing to
note is that you cannot get more than 5W out if your max input voltage
is limited to 100V and your (constant) current is .05A. So, you can
forget the 10W requirement because of your 100V limit.
It seems to me that, using the standard buck topology, you will need to
adjust your control loop (and thinking) as follows:
-Never let the input voltage get above 100V. As it approaches that
limit, increase the duty cycle. This is equivalent to current limit.
After all, if you are able to reduce the voltage while the current
remains the same, input and output power is reduced. Note that this
requires some kind of load just as in a current transformer.
-If the load is reduced, the voltage will tend to rise. Increase the
duty cycle even more to hold the voltage. By increasing the duty cycle
to a much higher value, you will cause the input voltage to plummet
which will reduce the available input power.
What is your maximum load resistance?
-If it can be open or very high, then you need to provide another device
at the input, perhaps a depletion FET capabale of about 100mA at a few
hundred volts to stop things when the duty cycle is commanded to be at
100% or a bit less.
Just some thoughts. I apologize if I have stepped on any toes.