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Magnetic force: An approach with Bernoulli's equation.

Discussion in 'Electronic Basics' started by Ka-In Yen, Jan 14, 2004.

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  1. Ka-In Yen

    Ka-In Yen Guest

    1. Abstract: In this paper, Bernoulli's effect is used to interpret
    the magnetic force.

    See my posting:

    All comments are welcome.

    Ka-In Yen

  2. Ka-In Yen

    Ka-In Yen Guest

    My dear friends,

    I am very sorry to disappoint you, the above derivation is
    incomplete. To eliminate L1 and L2 terms, negative potential
    masses have to be considered. A shematic diagram is shown as
    figure 2.

    ______________+______________________________ wire 1
    | (-q2,v2)
    V______________+_____________________________ wire 2

    Figure 2

    The whole electric wire is neutral; for every drifting electron(-),
    there is a resting ion(+). (-q1,v1) is charges of drifting electrons,
    and (+q1,0) is charges of resting ions. (-q2,v2) and (+q2,0) are
    same definition.

    1) To (-q1,v1) and (-q2,v2) pair, we have (m/R)*(v1+v2)^2 /2.
    2) To (-q1,v1) and (+q2,0) pair, we have (-m/R)*v1^2 /2.
    3) To (+q1,0) and (-q2,v2) pair, we have (-m/R)*v2^2 /2.

    1) + 2) + 3) = (m/R)*v1*v2 = mu_0 *q1*q2*v1*v2/(4*pi* R^2)
    = mu_0 *i1*i2 / (4*pi* R^2)

    Ka-In Yen

    How to correctly measure an unknown length with a clock.
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