# Magnetic force: An approach with Bernoulli's equation.

Discussion in 'Electronic Basics' started by Ka-In Yen, Jan 14, 2004.

1. ### Ka-In YenGuest

1. Abstract: In this paper, Bernoulli's effect is used to interpret
the magnetic force.

See my posting:

Ka-In Yen

回應留言

2. ### Ka-In YenGuest

My dear friends,

I am very sorry to disappoint you, the above derivation is
incomplete. To eliminate L1 and L2 terms, negative potential
masses have to be considered. A shematic diagram is shown as
figure 2.

(+q1,0)
(-q1,v1)
______________+______________________________ wire 1
^
|
R
(+q2,0)
| (-q2,v2)
V______________+_____________________________ wire 2

Figure 2

The whole electric wire is neutral; for every drifting electron(-),
there is a resting ion(+). (-q1,v1) is charges of drifting electrons,
and (+q1,0) is charges of resting ions. (-q2,v2) and (+q2,0) are
same definition.

1) To (-q1,v1) and (-q2,v2) pair, we have (m/R)*(v1+v2)^2 /2.
2) To (-q1,v1) and (+q2,0) pair, we have (-m/R)*v1^2 /2.
3) To (+q1,0) and (-q2,v2) pair, we have (-m/R)*v2^2 /2.

1) + 2) + 3) = (m/R)*v1*v2 = mu_0 *q1*q2*v1*v2/(4*pi* R^2)
= mu_0 *i1*i2 / (4*pi* R^2)

Ka-In Yen

How to correctly measure an unknown length with a clock.