C
Clunixchit
- Jan 1, 1970
- 0
Hello there,
I'm trying to understand how magic extracts resistance to a .sim file.
I'm using the default scmos.tech of magic and i have created a
rectangle (2 by 7) with polysilicium.
A sim file was extracted and the output is as follows:
| units: 100 tech: scmos format: MIT
R a_0_n2# 84
A second sim file was extracted from a similar rectangle but twice the
width that is (4 by 7) and the output is:
| units: 100 tech: scmos format: MIT
C a_0_n2# GND 2.9
R a_0_n2# 42
Ok if I follow the simple R = þ*L /A relation
where þ is the resistivity,
L : the length in this case 7
A :the area (H*W),
so R = (þ/H) L/W
by this ratio I have þ/H = 24.
Where and how magic sets þ/H to be 24 when the scmos.tech allows
2.0/1.6/1.2 µm ?
Is there a table somewhere which defines the resistance/µm for
* metal1,metal2,metal3
* ndiff,pdiff
* polysilicium
* ...
with respect to 2.0/1.6/1.2 µm ?
google wasn't useful this time.
regards,
Chitlesh
I'm trying to understand how magic extracts resistance to a .sim file.
I'm using the default scmos.tech of magic and i have created a
rectangle (2 by 7) with polysilicium.
A sim file was extracted and the output is as follows:
| units: 100 tech: scmos format: MIT
R a_0_n2# 84
A second sim file was extracted from a similar rectangle but twice the
width that is (4 by 7) and the output is:
| units: 100 tech: scmos format: MIT
C a_0_n2# GND 2.9
R a_0_n2# 42
Ok if I follow the simple R = þ*L /A relation
where þ is the resistivity,
L : the length in this case 7
A :the area (H*W),
so R = (þ/H) L/W
by this ratio I have þ/H = 24.
Where and how magic sets þ/H to be 24 when the scmos.tech allows
2.0/1.6/1.2 µm ?
Is there a table somewhere which defines the resistance/µm for
* metal1,metal2,metal3
* ndiff,pdiff
* polysilicium
* ...
with respect to 2.0/1.6/1.2 µm ?
google wasn't useful this time.
regards,
Chitlesh
