No. Your reading of 1 in the 20 mA range means 1 mA.
V
supply is the output voltage of your power source, the 5 V wall wart you want to use.
(5 V - 2.9 V)/1 mA = 2.1 V / 1 mA = 2.1
kΩ
The power rating of the resistor is P = 2.1 V * 1 mA = 2.1 mW. A standard 1/4 W resistor is more than good enough here.
With a 5 V wall wart (e.g. a typical off the shelf USB supply) you can only run the strips in parallel with one resistor for each strip (preferably). You may connect the strips in parallel and use a single resistor, but you'll have to calculate the resistor anew for the number of strips in parallel.
I prefer the one resistor per strip solution. That way a defect in one strip doesn't affect the other strips.
A 5 V power source is not suitable for series connecting these LED strips. In series connection teh min. voltage is 2*2.9 V = 5.8 V, more than the power supply delivers. You may use another type of wall wart with e.g. 6 V output voltage, but the 5 V USB types are ubiquitous and therefore the least expensive ones.
If you don't want to mess with the separate power supplies and resistors, you can get
mains powered fairy lights.