So should i just get a house plug and connect it (wire it) to the red wires. Which one of the wires is negative and which one is positive, of the black and white wires. If I wanted to put a on/off switch to this where would I put it? I'm not sure where the wires hook up on the LED ether?
You should at least wire an in-line glass cartridge fuse, about 1 A SLO-BLO, in series with one of the red wires before connecting it to a power cord, Maybe wire an in-line switch in series too so you can turn it on and off. You can purchase in-line fuse holders online, as well as in-line rocker switches designed for insertion in one wire of a 2-wire zip cord. Or try a big-box home improvement store for these parts as well as the zip cord. It is often less trouble to just buy a zip-cord type extension cord (usually 18 gauge wire) and cut the recpetacle(s) off the end, leaving the plug for the wall outlet.
You may need a cheap multimeter to help determine the polarity of the LED lamp. Unfortunately, the ohmmeter function won't be of much help. The forward voltage drop of the series-connected LEDs is about 35 V, way more than the little battery inside the VOM (volt-ohm-milliamp meter) can provide to forward bias the LED. So it will probably read "open circuit" using the ohmmeter function. So, use the power supply output to either forward bias or reverse bias the LED and determine which is which.
Here's how: Connect a 1000 ohm, 1 watt, resistor in series with the white wire of the power supply output (to limit current in case something goes wrong) and then connect the black power supply wire and the other end of the resistor to the LED. Since the polarity of the LED isn't obvious to you, there is a 50-50 chance of getting the polarity correct.
If the LED lights up (dimly because of the resistor limiting the current), you are done. Disconnect the resistor and connect the white wire to the LED. The black wire should already be connected to the LED. If it doesn't light up, reverse the leads going to the LED. The LED should now light up and you can remove the resistor for full-power operation.
