evol_w10lv
- Feb 19, 2013
- 73
- Joined
- Feb 19, 2013
- Messages
- 73
I have to calculate result of voltmeter and wattmeter. And also have to find effective current in the branches
Given:
e = 180 V
R1 = 8 Ohms
C1 = 0.0001 F
L1 = 0.0318 H
R2 = 4 Ohms
L2 = 0.0159 H
L3 = 0.0094 H
f = 50 Hz
Here I started calculations.
XL1 = 2*pi*f*L1 = 2*pi*50*0.0318 = ~10 Ohms
XC1 = 1/(2*pi*f*C1) = 1/(2*pi*50*0.0001) = ~31.8 Ohms
XL2 = 2*pi*f*L2 = 2*pi*50*0.0159 = ~5 Ohms
XL3 = 2*pi*f*L3 = 2*pi*50*0.0094 = ~3 Ohms
Z1 = R1 + j(XL1 - XC1) = 8 + j(10-31.8) = sqrt(8^2 + 21.8^2) * e^(-jarctg(21.8/8)) = ~ 23e^(-j69.85°) Ohms
Z2 = R2 + jXL2 = 4 + j5 = sqrt(4^2 + 5^2) * e^(jarctg(5/4)) = ~ 6.4e^(j51.34°) Ohms
Z3 = jXL3 = j3 = 3e^(j90°)
Z2 + Z3 = (Z3*Z2)/(Z3+Z2) = ((3e^(j90°))*(6.4e^(j51.34°)))/((3e^(j90°))+(6.4e^(j51.34°))) = 0.45 + j2.1 = ~2.16*e^(j77.91°) Ohms
Ztotal = (Z2+Z3) + Z1 = (0.45 + j2.1)+(8 + j(-21.8)) = 8.45-19.7j = 21.4*e^(-j66.78°)
Can someone can check weather imdependances are calculated wright? What is the next step to calculate current?
Given:
e = 180 V
R1 = 8 Ohms
C1 = 0.0001 F
L1 = 0.0318 H
R2 = 4 Ohms
L2 = 0.0159 H
L3 = 0.0094 H
f = 50 Hz
Here I started calculations.
XL1 = 2*pi*f*L1 = 2*pi*50*0.0318 = ~10 Ohms
XC1 = 1/(2*pi*f*C1) = 1/(2*pi*50*0.0001) = ~31.8 Ohms
XL2 = 2*pi*f*L2 = 2*pi*50*0.0159 = ~5 Ohms
XL3 = 2*pi*f*L3 = 2*pi*50*0.0094 = ~3 Ohms
Z1 = R1 + j(XL1 - XC1) = 8 + j(10-31.8) = sqrt(8^2 + 21.8^2) * e^(-jarctg(21.8/8)) = ~ 23e^(-j69.85°) Ohms
Z2 = R2 + jXL2 = 4 + j5 = sqrt(4^2 + 5^2) * e^(jarctg(5/4)) = ~ 6.4e^(j51.34°) Ohms
Z3 = jXL3 = j3 = 3e^(j90°)
Z2 + Z3 = (Z3*Z2)/(Z3+Z2) = ((3e^(j90°))*(6.4e^(j51.34°)))/((3e^(j90°))+(6.4e^(j51.34°))) = 0.45 + j2.1 = ~2.16*e^(j77.91°) Ohms
Ztotal = (Z2+Z3) + Z1 = (0.45 + j2.1)+(8 + j(-21.8)) = 8.45-19.7j = 21.4*e^(-j66.78°)
Can someone can check weather imdependances are calculated wright? What is the next step to calculate current?