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I've got B.O....

T

Tim Williams

Jan 1, 1970
0
http://webpages.charter.net/dawill/Images/RegBO.gif

http://webpages.charter.net/dawill/Images/RegBO1.jpg

Design: based around a blocking oscillator, a complete switching power
supply in only one transistor. The 1M resistor provides initial bias,
charging the 0.01 base bypass capacitor. When it reaches about 0.7V, the
MJE18008 kicks on. Due to positive feedback, it stays on, until collector
current reaches about 1.2A. At that point, the capacitor has discharged
enough that base current is falling. As a result, collector voltage begins
to rise, and by positive feedback, the base is slammed off rapidly.
Collector voltage rises to a peak around 500V, clamped by the RCD snubber
and slowed by the RC. The flyback pulse is dumped into the output filter
capacitor and the base bias supply (0.1 and 1N914, generating about -5V).
The transistor turns back on either when the base capacitor reaches
threshold, or if it's nearly there already, then when the inductor voltage
swings slightly below zero (due to ringing). In this way, the transistor
acts as a rudimentary BCM (Boundary Control Mode) switching supply.

To avoid dropping a large current from 160V, a bootstrap bias supply
furnishes base current. To control it, an optoisolator shunts the negative
supply, thus forcing more bias current into the base circuit, increasing the
charge rate of the 0.01 capacitor.

On the output side, a TL431 is used for voltage reference and error amp.
Unfortunately, the phase is wrong, so it has to be inverted with the 2N3906.
A ring-of-two current sink is used to bias the IR LED instead of a resistor,
to maximize startup current. As shown, the error amp starts around 2V, and
enters the linear range at 10.3V.

http://webpages.charter.net/dawill/Images/RegBO3.jpg

Here's the collector voltage waveform at 2.5A load. Essentially continuous
operation. Power input is about 40W, so efficiency is low, around 63%.
Most of this is dissipated in the transistor, but the small transformer is
getting warm, as is the diode and filter capacitor. The snubbers are also
burning a watt or so.

http://webpages.charter.net/dawill/Images/RegBO2.jpg

Current waveform for same conditions, measured across a 0.47 ohm emitter
resistor.

Tim
 
F

Fred Bartoli

Jan 1, 1970
0
Tim Williams a écrit :
http://webpages.charter.net/dawill/Images/RegBO.gif

http://webpages.charter.net/dawill/Images/RegBO1.jpg

Design: based around a blocking oscillator, a complete switching power
supply in only one transistor. The 1M resistor provides initial bias,
charging the 0.01 base bypass capacitor. When it reaches about 0.7V, the
MJE18008 kicks on. Due to positive feedback, it stays on, until collector
current reaches about 1.2A. At that point, the capacitor has discharged
enough that base current is falling. As a result, collector voltage begins
to rise, and by positive feedback, the base is slammed off rapidly.
Collector voltage rises to a peak around 500V, clamped by the RCD snubber
and slowed by the RC. The flyback pulse is dumped into the output filter
capacitor and the base bias supply (0.1 and 1N914, generating about -5V).
The transistor turns back on either when the base capacitor reaches
threshold, or if it's nearly there already, then when the inductor voltage
swings slightly below zero (due to ringing). In this way, the transistor
acts as a rudimentary BCM (Boundary Control Mode) switching supply.

To avoid dropping a large current from 160V, a bootstrap bias supply
furnishes base current. To control it, an optoisolator shunts the negative
supply, thus forcing more bias current into the base circuit, increasing the
charge rate of the 0.01 capacitor.

On the output side, a TL431 is used for voltage reference and error amp.
Unfortunately, the phase is wrong, so it has to be inverted with the 2N3906.
A ring-of-two current sink is used to bias the IR LED instead of a resistor,
to maximize startup current. As shown, the error amp starts around 2V, and
enters the linear range at 10.3V.

http://webpages.charter.net/dawill/Images/RegBO3.jpg

Here's the collector voltage waveform at 2.5A load. Essentially continuous
operation. Power input is about 40W, so efficiency is low, around 63%.
Most of this is dissipated in the transistor, but the small transformer is
getting warm, as is the diode and filter capacitor. The snubbers are also
burning a watt or so.

http://webpages.charter.net/dawill/Images/RegBO2.jpg

Current waveform for same conditions, measured across a 0.47 ohm emitter
resistor.

You can get rid of those 3904-06. Just tie the opto diode across the
TL431, with a series diode to control loop gain...
 
T

Tim Williams

Jan 1, 1970
0
Fred Bartoli said:
You can get rid of those 3904-06. Just tie the opto diode across the
TL431, with a series diode to control loop gain...

I tried that, but I don't think ~1.2Vf is enough for the 431, it wasn't
working. It needs more like 2.5V, dunnit?

The CCS still helps with startup and voltage range, which isn't a big deal
for the 431 (1-100mA is plenty of range), but it is rather wasteful for the
resistor otherwise doing the job.

Tim
 
T

Tim Williams

Jan 1, 1970
0
Cute. The MJE18008 Vce(sat) ramps up to ~15v toward the end of the ON
time. You could improve the efficiency a lot by fixing that.

Yeah, these things usually switch pretty nice, but it's hard to avoid
Vce(sat) rising in a simple BO like this. I suppose one solution might be
to increase the transconductance. Maybe a desat detector would sharpen
things, that and increasing base current.
The inductor ringing seems to be triggering a few runt ON cycles right
after the real deal, e.g. the spikes at division 0.7 and 3.3 on the
current waveform. Those are lossy.

Hmm, collector voltage is also falling below +V at that point, so it
probably would be turning on slightly, or getting close to it.

The transformer was thrown together, no particular thought given to leakage.
The RC snubber gets pretty hot. The waveforms are downright ugly without
the snubber, even the flyback peak is trashed. A better transformer would
do a lot towards making everything work better.

Tim
 
H

Hammy

Jan 1, 1970
0
http://webpages.charter.net/dawill/Images/RegBO.gif

http://webpages.charter.net/dawill/Images/RegBO1.jpg

Design: based around a blocking oscillator, a complete switching power
supply in only one transistor. The 1M resistor provides initial bias,
charging the 0.01 base bypass capacitor. When it reaches about 0.7V, the
MJE18008 kicks on. Due to positive feedback, it stays on, until collector
current reaches about 1.2A. At that point, the capacitor has discharged
enough that base current is falling. As a result, collector voltage begins
to rise, and by positive feedback, the base is slammed off rapidly.
Collector voltage rises to a peak around 500V, clamped by the RCD snubber
and slowed by the RC. The flyback pulse is dumped into the output filter
capacitor and the base bias supply (0.1 and 1N914, generating about -5V).
The transistor turns back on either when the base capacitor reaches
threshold, or if it's nearly there already, then when the inductor voltage
swings slightly below zero (due to ringing). In this way, the transistor
acts as a rudimentary BCM (Boundary Control Mode) switching supply.

To avoid dropping a large current from 160V, a bootstrap bias supply
furnishes base current. To control it, an optoisolator shunts the negative
supply, thus forcing more bias current into the base circuit, increasing the
charge rate of the 0.01 capacitor.

On the output side, a TL431 is used for voltage reference and error amp.
Unfortunately, the phase is wrong, so it has to be inverted with the 2N3906.
A ring-of-two current sink is used to bias the IR LED instead of a resistor,
to maximize startup current. As shown, the error amp starts around 2V, and
enters the linear range at 10.3V.

http://webpages.charter.net/dawill/Images/RegBO3.jpg

Here's the collector voltage waveform at 2.5A load. Essentially continuous
operation. Power input is about 40W, so efficiency is low, around 63%.
Most of this is dissipated in the transistor, but the small transformer is
getting warm, as is the diode and filter capacitor. The snubbers are also
burning a watt or so.

http://webpages.charter.net/dawill/Images/RegBO2.jpg

Current waveform for same conditions, measured across a 0.47 ohm emitter
resistor.

Tim

It's a self oscillating fly back. It's been around for a while.

http://i46.tinypic.com/5y9oae.png

Analysis and Design of Self-Oscillating Flyback Converter

http://www.dianyuan.com/bbs/u/56/296581188382516.pdf

Several patents based on the same basic circuit with minor tweaksl.
 
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