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Inductor help

Discussion in 'Electronics Homework Help' started by ElectStudent, Apr 8, 2014.

  1. ElectStudent

    ElectStudent

    13
    0
    Apr 8, 2014
    Please see attachment.

    In this circuit, the graph shows that the current rises linearly.
    However, wouldn't there be a limit to how much it rises and is it actually linear because the inductor should resist current changes shouldn't it?
     

    Attached Files:

  2. ElectStudent

    ElectStudent

    13
    0
    Apr 8, 2014
    Are these graphs correct?

    Please see attachment.

    In this circuit, the graph shows that the current rises linearly.
    However, wouldn't there be a limit to how much it rises and is it actually linear because the inductor should resist current changes shouldn't it?
     

    Attached Files:

  3. BobK

    BobK

    7,626
    1,654
    Jan 5, 2010
    The equation for an inductor is

    dI/dt = V/L

    So, with a fixed voltage across the inductor, the current will rise linearly. This is with ideal components, i.e. a voltage source that has no current limit or internal resistance, and an inductor with no series resistance. In the real world it will be limited and non-linear as you imagine.

    Bob
     
  4. ElectStudent

    ElectStudent

    13
    0
    Apr 8, 2014
    Thank you that helped a lot. I was also wondering how the current can rise so fast in an inductor? Because i was thinking inductors resist current change
     
  5. (*steve*)

    (*steve*) ¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd Moderator

    25,191
    2,693
    Jan 21, 2010
    The rising current *is* the inductor resisting a change in current.

    It doesn't instantaneously rise to some figure does it?

    Rather than stopping at some point, if the inductor saturates (which a theoretical inductor won't) the current will spike.
     
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