# Important ! for u

Discussion in 'Electronic Basics' started by joshua, Feb 22, 2006.

1. ### joshuaGuest

Hi All,
what is the meaning of 24bit,16 bit in Analog to Digital converter.
I think it is for resolution. I am not understood properrly any one
help me.
Kind Regards,
Joshua

2. ### Pooh BearGuest

It is indeed resolution.

For someone supposedly involved in electronic design you don't know
very much do you ?

Graham

3. ### Bob MastaGuest

A 16-bit converter has 2^16 possible states;
a 24-bit converter has 2^24. But note that
in the real world this difference is *very* hard to
realize, due to the noise floor of typical analog
circuits. That's because there are definite
limits on how high the input voltage can be,
so you have to try to resolve ever-lower voltages
to increase resolution. With a 16-bit ADC having
a 0-4.096 V input range, the resolution is 62.5 microvolts.
With a 24-bit ADC covering the same range, the
resolution is 0.244 microvolts. Not many circuits
with noise that low!

Best regards,

Bob Masta

D A Q A R T A
Data AcQuisition And Real-Time Analysis
www.daqarta.com
Home of DaqGen, the FREEWARE signal generator

4. ### ChrisGuest

Hi, Joshua. May I suggest that you find a tutor, and pay him to help
you with your school project.

You are in way over your head, and a newsgroup is not the appropriate
place to get the kind of timely, intensive help you apparently need.
This newsgroup is also not an appropriate place for homework questions.

I'm sure you could either place a post on your school bulletin board,
or advertise to find an upperclassman who is willing to be employed.

Good luck
Chris

5. ### PeteSGuest

To a certain extent I agree, yet the OP has chosen s.e.b. (rather than
s.e.d. at least) and at least has asked a question (albeit not using
particularly precise grammar and perhaps even wishes to learn - who
knows.

I always thought s.e.b. might be the appropriate place for someone to
ask a question on an electronics subject about which they have no
knowledge, especially if they admit to not knowing

Cheers

PeteS

6. ### Michael A. TerrellGuest

For someone posting on the basics newsgroup you are rather rude. If
you don't want to help someone, don't make fun of them. this isn't SED,
and the OP isn't claiming to be an EE, so get over yourself.

--
Service to my country? Been there, Done that, and I've got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida

7. ### ChrisGuest

Hi, Pete. You're right, of course. A few people have said the
unofficial motto of s.e.b. should be that "There's no question too
basic for this newsgroup". We don't want to scare off the newbies.

Look at his 15 topic posts over the last two weeks in s.e.b., s.e.d.
and sci.electronics.components, and judge for yourself. Look
particularly at the posts relating to his weigh scale project, load
cells and the LCD display. I'm thinking in particular about his post
early this morning in s.e.d. "Hi, All (Load Cell)", and the several

He really needs much more help than the advice he can get here, and
he's not being fair to himself looking for that help in newsgroups.
His project will never get done by the end of the semester. And
incidentally, I've heard it expressed a few times here that the
function of homework and class projects is to reinforce learning, and
we're defeating that purpose by serving up answers to homework
questions.

Joshua is apparently in so far over his head that a good answer to his
question might not even help. If he does understand anything about
digital logic and counting, he doesn't indicate it. And if he did, the
most appropriate response here would actually be to have somebody find
out what Digital Logic textbook they're using in his class, obtaining
the book, then typing up the chapter on ADCs in a post (including
illustrations in ASCII art ;-). He really should just read it himself,
and purchase the textbook if he hasn't done so. Sometimes there are no
shortcuts to learning -- you just have to do it. We did.

Every college and technical school has sharp kids who are looking for a
few extra honest coins (I would have included myself among those back
in the day). It might be better for him to just find one, and get some
tutoring and/or design help with his project. If he doesn't understand
the classwork, several hours a week of one-on-one intensive help might
get him on track quickly without a whole lot of expense.

I do like the fact that nobody's flaming him here, including me. I
wish Joshua well, and hope he gets all the help he needs.

Cheers
Chris

8. ### JamieGuest

you are correct, its basicly how
accurate you can decode an analog
signal.
results of the lowest and highest
value would most likely be the same
as lower bit converters how ever,
each reading you get is of larger
scale number between the same range
as that of the lower bit converters.
for example..
an 8 bit coverter has a range of
0..255 , 0 = 0 volts, 255 = 10 volts for example.
a 16 bit converter has a range of
0..65535, 0 = 0 volts, 65535 = 10 volts...

you can see here that between the low and
high you can get more accurate readings.
now sampling rates is still another story.

9. ### PeteSGuest

Well, there are some who seem to continue to ask questions on
'advanced' things without asking for basics first , although that (for
a few posts anyway) is perhaps understandable - they don't know there
are basics underlying the question.

After a few such posts, provided we've explained that the OP might like
to ask very basic questions where we could even point to a resource on
said basics, it does tend to get old.

That said, I didn't see the posts in question (I was netless for a
while on a job - aarrgghh) so I don't know this particular history

I think I get more pee'd at poor grammar and spelling than apparently
silly questions - after all, if I can't understand the question,
there's little hope of answering it !

I don't doubt you had no intention to flame

Cheers

PeteS