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HOW TO SIMULATE THE PSRR

Discussion in 'Electronic Design' started by a, Jan 9, 2004.

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  1. a

    a Guest

    Hi there :
    I try to simulate the PSRR and use the book "CMOS ANALOG CIRCUIT DESIGN ,
    ALLEN, 2nd" ,
    and the example is on page 320.

    But I can't get the same result as fig6.6-18 , why ?
    Please tell me which mistake I made.
    Thank you



    *EXAMPLE
    ..OPTION
    *LIMPTS=501

    ..SUBCKT OPAMP 1 2 6 8 9
    M1 4 2 3 3 NMOS1 W=3U L=1U AD=18P AS=18P PD=18U PS=18U
    M2 5 1 3 3 NMOS1 W=3U L=1U AD=18P AS=18P PD=18U PS=18U
    M3 4 4 8 8 PMOS1 W=15U L=1U AD=90P AS=90P PD=42U PS=42U
    M4 5 4 8 8 PMOS1 W=15U L=1U AD=90P AS=90P PD=42U PS=42U
    M5 3 7 9 9 NMOS1 W=4.5U L=1U AD=27P AS=27P PD=21U PS=21U
    M6 6 5 8 8 PMOS1 W=94U L=1U AD=564P AS=564P PD=200U PS=200U
    M7 6 7 9 9 NMOS1 W=14U L=1U AD=84P AS=84P PD=40U PS=40U
    M8 7 7 9 9 NMOS1 W=4.5U L=1U AD=27P AS=27P PD=21U PS=21U
    CC 5 6 3P
    IBIAS 8 7 30U

    ..MODEL NMOS1 NMOS VTO=0.7 KP=110U GAMMA=0.4 LAMBDA=0.04 PHI=0.7
    +MJ=0.5 MJSW=0.38 CGBO=700P CGSO=220P CGDO=220P CJ=770U CJSW=380P
    +LD=0.016U TOX=14N

    ..MODEL PMOS1 PMOS VTO=-0.7 KP=50U GAMMA=0.57 LAMBDA=0.05 PHI=0.8
    +MJ=0.5 MJSW=0.35 CGBO=700P CGSO=220P CGDO=220P CJ=560U CJSW=350P
    +LD=0.014U TOX=14N
    ..ENDS

    X1 1 3 3 4 5 OPAMP

    VDD 4 0 DC 2.5 AC 1.0
    VSS 0 5 DC 2.5
    CL 3 0 20P

    VIN+ 1 0 PWL (0 -2 10N -2 20N 2 2U 2 2.01U -2 4U -2 4.01U -.1
    +6U -.1 6.01U .1 8U .1 8.01U -.1 10U -.1)

    ..DC VIN+ -2.5 2.5 0.1
    ..PRINT DC V(3)

    ..TRAN 0.05U 10U 0 10N
    ..PRINT TRAN V(3) V(1)

    ..AC DEC 10 0.1 1000MEG
    ..PRINT AC VDB(3) VP(3)

    ..PROBE
    ..END
     
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