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How to calculate output voltage for ac coupled inverting amplifier

Discussion in 'LEDs and Optoelectronics' started by sharimin, Dec 17, 2013.

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  1. sharimin

    sharimin

    8
    0
    Dec 17, 2013
    Please help me,
    How to calculate the output voltage for this ac coupled inverting amplifier
    ac coupled.JPG
     
  2. duke37

    duke37

    5,361
    767
    Jan 9, 2011
    The gain of a virtual earth amplifier is just output resistance divided by the input resistance, in this case 40000/56 = 714.

    There are two things to be considered;-
    1. The operational amplifier must have a gain much higher than this.
    2. The input capacitor will provide a significant impedance and lower gain at lower frequencies. I suggest you put this circuit into a simulation program to se the effect.
     
  3. mursal

    mursal

    75
    0
    Dec 13, 2013
    The voltage divider R3, R4 gives a bias voltage of 2Volts on the non inverting input. So the AC waveform will swing + and - on this bias voltage.
    Vout = (-R2/R1)Vin + Vbias
    Its a while since I covered this material, so hold tight until someone else has a look, I'm probably missing something.
     
  4. sharimin

    sharimin

    8
    0
    Dec 17, 2013
    from simulation : if the input is 10.603V, the output is 2.377KV..

    but, i want to know how the calculation and the formula..

    pls help me..
     
  5. mursal

    mursal

    75
    0
    Dec 13, 2013
    Its a small signal amplifier (low voltage) try this link Click
     
  6. duke37

    duke37

    5,361
    767
    Jan 9, 2011
    mursal has given the formula, you should be able to evaluate that.

    The op-amp cannot provide more voltage than its power supply voltage so 2.337kV (not 2.337KV !) is absurd. With an output swing of 1V, the maximum signal input would be 1/714 = 1.4mV
     
  7. sharimin

    sharimin

    8
    0
    Dec 17, 2013
    so this circuit is wrong??

    thank you for the information, i will try with the new circuit.
     
  8. (*steve*)

    (*steve*) ¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd Moderator

    25,386
    2,772
    Jan 21, 2010
    Well, it's wrong in that you'll never get 2.33kV (nor will any simple op-amp circuit)
     
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