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How to balance the bridge?

charmcaster.engg

Mar 20, 2014
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mcq6_1008_1.gif


In the given circuit, what is RUNK equal to if RV must be adjusted to 1,232
omega.gif
in order to balance the bridge?
 

KrisBlueNZ

Sadly passed away in 2015
Nov 28, 2011
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OK, think about what "balancing the bridge" means. It means that there is no voltage across the meter, right?

So the left and right hand sides of the bridge are both voltage dividers, supplied from the same source voltage, VS. The right hand side will divide VS by a fixed ratio, which can be calculated from the two resistor values. This will leave a certain proportion of VS across the 100Ω resistor, and the rest across the 560Ω resistor, right? Can you calculate the proportions of VS that will appear across each of those resistors?

Now you have a voltage divider on the other side as well, and they have told you that when the bridge is balanced, RV is 1232Ω. Can you use the voltage divider formula to calculate what RUNK will be?
 

charmcaster.engg

Mar 20, 2014
79
Joined
Mar 20, 2014
Messages
79
OK, think about what "balancing the bridge" means. It means that there is no voltage across the meter, right?

So the left and right hand sides of the bridge are both voltage dividers, supplied from the same source voltage, VS. The right hand side will divide VS by a fixed ratio, which can be calculated from the two resistor values. This will leave a certain proportion of VS across the 100Ω resistor, and the rest across the 560Ω resistor, right? Can you calculate the proportions of VS that will appear across each of those resistors?

Now you have a voltage divider on the other side as well, and they have told you that when the bridge is balanced, RV is 1232Ω. Can you use the voltage divider formula to calculate what RUNK will be?
I got ratio as 0.178. and the R UNK as 220. Am I right?
 

KrisBlueNZ

Sadly passed away in 2015
Nov 28, 2011
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Yes that's what I get. You've done it an even simpler way than I suggested. It's just all about ratios.
 
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