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5056`-56``-34`

Answer :

3Solution :

The equation of radical axis ( i.e., common chord ) of the two circles is <br> `10x+4ya-a-b=0` (1) <br> The center of the first circle is `H(-4,-4)` <br> Since the second circle bisects the circumference of the first circle, the center `H(-54,-4)` of the first circle must lie on the coomon chord (1). Therefore, ltbr. `-40-16-1-b=0` <br> or `a+b= -56`Transcript

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00:00 - 00:59 | question is if the circumference of a circle X square + Y square + 8 x + 8 Y - b is equals to zero is bisected by X square + Y square - 2 X + 4 Y + C is equal to zero then we have to find a + b options are a 5056 c - 56 and D is -13 this circle represent the equation of circle Aspirin and the circle represents the equation of circle as to as it is it is given in the question that circumference of circle is bisected so when we buy said both the circle the chord joining the points is a diameter of a circle is fun for this represents the diameter of a circle has done so far as we will write the equation of circle as one that is X square + Y square + 8 x + |

01:00 - 01:59 | 8 by minus b is equal to zero now on comparing with the standard equation of circle we can write its Centre as if that is -4 and equation of circle X square + Y square - 2 X + 4 Y + Y is equals to zero the comparing it again with general equation we got it Centre as 1 -2 of a circle is a common to both so we can write the equation of the equation of common chord common chord of the circle given sms2 is equal to zero so we will right here and |

02:00 - 02:59 | minus 2 is equal to zero and we will write equation is X square + Y square + 8 x + 8 Y minus b minus x square + Y square + 4 Y + 1 is equal to zero now opening a bracket and solving this equations we get 10 X + 4 Y minus minus b is equal to zero because this item will cancel out and y square time will can this equation represents the diameter of the circle also so it passes to the centre of circle as 14 centre of circle as many - 4 - 44 this point satisfy this equation for get 10 into minus 4 + 4 into minus 4 minus a minus b is equal to zero |

03:00 - 03:59 | now solving this we get it is equals to a + b so we have to calculate the sand storm comes to be - 56 is equals to a + b minus 2 find this only so options is a correct answer |

**Standard equation of circle**

**General Equation of Circle When the circle passes through the origin.**

**General Equation of Circle When the circle touch x axis and y axis .**

**General Equation of Circle When the circle touches both the axis.**

**Important points to remember**

**Find the Equation; radius; center of the circle and its x intercept and y intercept ?**

**Theorem:- Prove that the equation `x^2+y^2+2gx+2fy+c=0` always represent a circle whose centre is `(-g;-f)` and radius `sqrt(g^2+f^2-c)`**

**Diameter form of the circle**

**Parametric form of circle**

**Equation of a circle passing through 3 points**