How can I simplify it? equivalent resistance

[riko]

Could you please help me with this. I dont know how to simplify it :C



Moderators note : shown image full size

 

[bertus]

Hello,

Have a look at the schematic.
Wich resistors are in series and wich are in parallel?

Have a look at this page from the textbook:
What are “Series” and “Parallel” Circuits?

Bertus

 

[Martaine2005]

Start from the far right. Calculate resistors in series and replace those with a single resistor value. Then working left, calculate the resistors in parallel and replace them with a single value.

Martin

 

[riko]

R57 = R5 + R7
1/R576 = 1/R57 + 1/R6
R5764 = R576 + R4
R12 = R1 + R2
1/R123 = 1/R12 + 1/R3
R1234567 = R5764 + R123

Like that?

 

[bertus]

Hello,

That is not all correct.
Have a look at the schematic when we draw it a little different:

Can you now tell wich resistor is in series and wich in parallel?

Bertus

 

[riko]

(R3,R4,R6,R57) = x = parallel, then series = x + R2 and x + R2 are parallel if think good

 

[bertus]

Hello,

What about R1?

Bertus

 

[riko]

Oh i forgot to write it. (x + R2) = y, y and R1 are parallel

 

[bertus]

Hello,

That is correct when R57 is R5+R7.

Bertus

 

[riko]

Yes!
Thank you very much for your help

 

[TommyN]

View attachment 50625

Could you please help me with this. I dont know how to simplify it :C



Moderators note : shown image full size

Riko, there appear to be three nodes which are disguised by the schematic layout HINT

Another way of looking at the network of resistors may quickly simplify how the resistances in the series and parallel configuration they are shown in. Hope that helps TommyN

 

[Harald Kapp]

That is what @bertus did in post #5.

 

[equ]

View attachment 50625

Could you please help me with this. I dont know how to simplify it :C



Moderators note : shown image full size

Try here:

 

[Harald Kapp]

@equ : This thread will soon be 2 years old without any further contribution -> locked