Help to understand opamp compensation

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I've found this interesting lecture
www.analogzone.com/acqt0704.pdf
but i don't understand open loop gain with resistor series capacitor
as load.In fig. 6.15 opamp's open loop gain is represented: it is
calculated (i think) at node Vout of fig 6.14, so pole is equal to 1/
(Ro+Riso)*Cl. I don't understand how zero is obtained....
Can you help me?
Thanks

 

[neon]

Undestand this any amplifier will oscillate at higher frequency if when you cross the 0 Db point at a slope greater then one. What you read is spice simulation . That is not the real world . Spice can make do anything you want .