Help Joule Thief Circuit

[Lawnd]

i was completed my small project with simple joule thief circuit, and I made inductor with L1 = 10L L and L2 = 110 L with same in string diameter. Input is 1,5 V with the output is -16 V.
and my question,
-Why the output is -16V?
-What components should be added so that the output is not negative and stable?

 

[Harald Kapp]

Why the output is -16V?

your windings ratio is 11/1 with the higher number of windings on the output. Therefore you can expect 11*1.5 V = 16.5 V at the output. You'll measure a bit less due to losses in the circuit.

-What components should be added so that the output is not negative and stable?

None. This is not possible with a simple joule thief circuit. The output is negative by principle. To get a positive outpit voltage you'd need a voltage inverter circuit which is so (comparatively) complex it negates the use of a joule thief to harvest the last bit of energy from a battery.
The same reason goes for regulating the output voltage.
If you need a regulated positive output voltage from a 1.5 V input use a boost regulator circuit.

 

[WHONOES]

The joule thief circuit can be made to work and give a positive voltage. Just add a tertiary winding (third) winding to control the base circuit then, you can do as you please with the secondary.
See attachment below.