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Food Processor

Harald Kapp

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O.K., that was a misunderstanding on my side. Sorry.
 

Harald Kapp

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Thank you ADRT, what you said is exactly what I am thinking now, with that very low OHM I should be still be able to see some voltage between 1 & 3, but there is No Voltage
You will see a voltage across this resistor only if a current flows. Since there is no currrent - foof processor doesn't work - there is also no voltage.

Even if the food processor were working, a quick calculation shows that you can expevt only a small voltage:
Let's assume the food processor takes up 1000W at 110V.
This makes for 9.1A.
9.1A through 0.15Ω gives a voltage drop of 1.36V - proportionally more or less depending on the power uptake of the machine.
 

Hamid mah

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You will see a voltage across this resistor only if a current flows. Since there is no currrent - foof processor doesn't work - there is also no voltage.

Even if the food processor were working, a quick calculation shows that you can expevt only a small voltage:
Let's assume the food processor takes up 1000W at 110V.
This makes for 9.1A.
9.1A through 0.15Ω gives a voltage drop of 1.36V - proportionally more or less depending on the power uptake of the machine.
Thanks Harald, do you agree if I just by Pass the Resistor? by a wire and see how that works?
 

Harald Kapp

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Not a very good idea. This resistor is there for a reason. I can't know exacty why, but it may serve as current sense resistor, current limiter or whatnot. Bette rget a 0.15Ω resistor rated 4W as a replacement.
 
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