Thank you ADRT, what you said is exactly what I am thinking now, with that very low OHM I should be still be able to see some voltage between 1 & 3, but there is No Voltage
You will see a voltage across this resistor only if a current flows. Since there is no currrent - foof processor doesn't work - there is also no voltage.
Even if the food processor were working, a quick calculation shows that you can expevt only a small voltage:
Let's assume the food processor takes up 1000W at 110V.
This makes for 9.1A.
9.1A through 0.15Ω gives a voltage drop of 1.36V - proportionally more or less depending on the power uptake of the machine.
You will see a voltage across this resistor only if a current flows. Since there is no currrent - foof processor doesn't work - there is also no voltage.
Even if the food processor were working, a quick calculation shows that you can expevt only a small voltage:
Let's assume the food processor takes up 1000W at 110V.
This makes for 9.1A.
9.1A through 0.15Ω gives a voltage drop of 1.36V - proportionally more or less depending on the power uptake of the machine.
Not a very good idea. This resistor is there for a reason. I can't know exacty why, but it may serve as current sense resistor, current limiter or whatnot. Bette rget a 0.15Ω resistor rated 4W as a replacement.