P
Peter
- Jan 1, 1970
- 0
I designed the circuit listed below in the simulator using an ideal op-amp.
Rf = 20k
R1 = 2k
C1 = 4uF
the way it was designed: The Rf is the feedback resistor and R1 and C1 are
in series to ground. The input is 20Hz 2Vp-p on the non-inverting input. I
calculated a gain of 8.08 so the output should be 16.2Vp-p. But the
simulator shows an output of 15.6Vp-p.
Now this isn't a huge difference, but since I used exact numbers in the
calculator (i.e. didn't round off) and I used an ideal op-amp, shouldn't I
have the exact numbers???? I even calculated a 45 degree phase shift and
the simulator has a 38 degree phase shift.
If anyone can assist me, I'd appreciate it.
Thanks
Rf = 20k
R1 = 2k
C1 = 4uF
the way it was designed: The Rf is the feedback resistor and R1 and C1 are
in series to ground. The input is 20Hz 2Vp-p on the non-inverting input. I
calculated a gain of 8.08 so the output should be 16.2Vp-p. But the
simulator shows an output of 15.6Vp-p.
Now this isn't a huge difference, but since I used exact numbers in the
calculator (i.e. didn't round off) and I used an ideal op-amp, shouldn't I
have the exact numbers???? I even calculated a 45 degree phase shift and
the simulator has a 38 degree phase shift.
If anyone can assist me, I'd appreciate it.
Thanks