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energy of a photon

Discussion in 'Electronic Design' started by Jamie, Jul 2, 2011.

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  1. Jamie

    Jamie Guest

    Hi,

    Ok so this formula E = h*c/λ gives the energy of a "photon". To
    simplify that formula, it could be thought of as E = amplitude /
    wavelength, with the h constant scaling the amplitude correctly, and the
    c constant scaling the wavelength constant correctly.

    One interesting thing from this formula is it apparently shows that all
    "photons" aka electromagnetic waves resulting from electron orbital
    emissions, have the same amplitude! So this must mean that all electron
    orbital emissions and absorptions (which are frequency keyed) must all
    emit or absorb electromagnetic waves with the same fixed amplitude,
    regardless what the orbital number is. I find that to be quite amazing
    and hard to understand why that would occur.

    cheers,
    Jamie
     
  2. Jamie

    Jamie Guest

    Ahh I think I figured it out, this amplitude is proportional to the the
    electron's angular momentum (which is a constant I guess)

    http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/hydazi.html#c3

    cheers,
    Jamie
     
  3. Jamie

    Jamie Guest

    Hi,

    New idea: Planck's constant describes the constant angular momentum
    transfer when an electron changes orbital states.

    From this page:

    http://en.wikipedia.org/wiki/Angular_momentum#Angular_momentum_in_quantum_mechanics

    "an electron standing at rest has an angular momentum of hbar/2."

    This shows that it is the electron's angular momentum that is the
    inherent source of Planck's constant, if the electron had inherently
    more "at rest" angular momentum, then the photoelectric emission graph
    of voltage over frequency would have a higher slope and Planck's
    constant would be a proportionately different number.

    from this page:
    http://en.wikipedia.org/wiki/Planck_constant

    "The Planck constant has dimensions of physical action; these are the
    same as those of angular momentum"

    So right there the Planck units even match those of the electron's
    angular momentum.

    Einstein made up the photon to explain Planck's constant and the
    photoelectric effect when really he should have picked the electron!

    cheers,
    Jamie
     
  4. Jamie

    Jamie Guest

    Hi,

    I don't typically think of photons rattling around, as I don't believe
    in them either. However for the emission of electromagnetic waves from
    an atom, each emission must have a fixed amplitude, as seen from the
    photoelectric experiments. That amplitude is defined by Planck's
    constant, which I think is defined itself by the electron angular
    momentum, so that when an atom emits a "photon", the amplitude of the
    photon is directly related to the electrons angular momentum. That
    shows Planck's constant is derived from matter and not from quantized
    electromagnetic fields aka "photons".

    cheers,
    Jamie
     

  5. How about having the amplitude as square root
    of the power ? As just the energy is given,
    we need a time. Here comes the interesting relation.
    We'd naturally assign one wavelength giving
    a time of λ/c = 1/frequency. But then the
    bandwidth of the photon would be huge and the
    spectrum continuous. And a line spectrum requires
    the photon to be infinitely long...
    We can trade spatial uncertainty against frequency
    uncertainty and arrive at gaussian pulses, the
    eigenfunctions of the Fourier transform. Thus the
    length of a photon is (low natural number)/frequency.

    For further reading search for "squeezed photons"

    Rene
     
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