M
MRW
- Jan 1, 1970
- 0
Hi again!
Image link:
http://img50.imageshack.us/img50/1584/micpreampac2.jpg
In regards to the circuit above, can someone explain to me the part of
the circuit circle in red? I understand that for most electret mics I
need to bias it and that the resistor connected to my bias source is
normally my source resistance. In the red circle, why is the bias
network setup that way?
Also, for the circuits circle in blue, I just need to verify that I'm
looking at it the right way. For the 10k and 1uF, the corner frequency
is around 15Hz and for the other network is around 16kHz. So are the
following the right assumptions:
- if my input signal is 20Hz, then my closed-loop gain is around 11?
- at 17kHz, the opamp would just be a voltage follower?
- at 17kHz, the 10kohm op amp is there to match the input bias
currents?
Thanks!
Image link:
http://img50.imageshack.us/img50/1584/micpreampac2.jpg
In regards to the circuit above, can someone explain to me the part of
the circuit circle in red? I understand that for most electret mics I
need to bias it and that the resistor connected to my bias source is
normally my source resistance. In the red circle, why is the bias
network setup that way?
Also, for the circuits circle in blue, I just need to verify that I'm
looking at it the right way. For the 10k and 1uF, the corner frequency
is around 15Hz and for the other network is around 16kHz. So are the
following the right assumptions:
- if my input signal is 20Hz, then my closed-loop gain is around 11?
- at 17kHz, the opamp would just be a voltage follower?
- at 17kHz, the 10kohm op amp is there to match the input bias
currents?
Thanks!