Connect with us

Determining Wattage Consumed by a Hair Dryer????

Discussion in 'Electronic Basics' started by NYC Doc, Sep 6, 2005.

Scroll to continue with content
  1. NYC Doc

    NYC Doc Guest

    Recently, while perusing Ebay, I noticed an auction (actually several) for a
    2800 watt "Volcano" hair dryer. This was 800 more watts than I had ever
    seen. My initial reaction was that it couldn't be possible because this
    would lead to triggered circuit breakers. So I purchased a hair dryer in
    addition to a non-contact current meter.

    Using a split extension cord, it was registering 9.8 amps, slightly less
    than my 1800 Conair dryer. So, it is safe to say that [most of the]
    voltage is in phase with current? I would assume that 99% of the energy
    goes to the heating element.

    If this is this case, then the power should be

    9.8 * 2 *120 (approx) * 0.99 ???

    = 2156 ?
  2. For a resistive load (and this is a good example of one of those)
    watts is RMS Amperes times RMS volts, so 9.8 amperes times 120 volts =
    1176 watts. They lied.
  3. Ralph Mowery

    Ralph Mowery Guest

    The total wattage is the current times the voltage. 9.8 *120 = 1176 watts.
    I don't know how you managed to put the 2 in your equation. The dryer is
    purely resistance (not counting the motor which should be a very small draw)
    so all the current would be converted to heat.
    If it was a 2800 watt unit , it would draw 23 amps. That is 3 more than
    than the wall sockets are rated at the most. I doubt that any dryers would
    really be rated over 1500 watts if that was their true value. That is
    almost the limit of most house circuits, especially if they have anything
    else on them.

    I did a quick check of one at the house. It is rated 1875 watts. It
    actually uses 11 amps on the highest heat. The motor uses about 1.5 amps.
    This only leaves 9.5 amps for the heater. At most it could be rated 120 *
    11 = 1320 watts. This is for the motor and heater.

    I think they just pull numbers out of the air for the dryers. I guess they
    could multiply it by 1.4 to give it a fake peak wattage instead of a RMS
    wattage. That would make it about right.
  4. NYC Doc

    NYC Doc Guest

    Isn't AC current doubled? Based on various tests, it appeared that the
    current measurement only represents 1/2 of the current. For a 1000 watt
    device, I was getting 5 amps, for a 2000 watts device, I was getting 10

  5. AC current measured by almost any meter is the RMS value. The peaks
    are the square root of 2 (1.414) times that. Same with voltage. The
    meter readings are useful, because you simply multiply the meter
    current by the meter voltage (for a resistive load) to get average
    power. The instantaneous power is popping up to twice that, but also
    going to zero, twice per cycle. But the normal use of Watts is the
    average value of that swing.
    Then your measurement is off (for whatever reason) and you may need
    that factor of approximately 2 to get the true RMS current. But your
    meter is not right. Is it a clamp on ammeter? Are you passing only
    one wire through it only once, and keeping the other conductor well
    away from the clamp? How do you know the other loads are nay more
    honest than the hair dryer?

    By the way, it is illegal in the US to sell any appliance to be
    plugged into a household 15 ampere receptacle that draws more than 12
    amperes (except for a brief burst at turn on). That limits the power
    to no more than 12*120=1440 watts.
  6. Bob Eldred

    Bob Eldred Guest

    There is no "2" or doubling of the current. I don't know where you got that
    idea? It's just volts times amps in RMS values or in DC values in a DC
  7. Ralph Mowery

    Ralph Mowery Guest

    On a standard 60 hz circuit the current and voltage should be measured with
    a meter that is calibrated in RMS. You multiply them together toget the
    wattage. Either your meter is wrong or the loads you are looking at are

    I suspect the hair driers must be rated like some of the computer speakers I
    have seen. They will be rated at 40 watts and driven by a small wall cube.
    If you open them up they may be marked for 2 watts. Someone came up with
    the advertising hype that for a milisecond or so they could have a peak of
    the 40 watts. Pure BS for advertising.
    Just some more of the junk advertising like the ads you see on TV for some
    cars and trucks. Saw one ad where a 4 wheeler comes up to the barn and goes
    up the outside wall..try doing that in the real world.
  8. Kitchen Man

    Kitchen Man Guest

    You didn't factor in the SQRT-2 advertisement allowance :)

    1440 * 1.414 ~= 2037, so I can see why the 2800W rating would be 800W
    higher than the OP had ever previously seen advertised. Reckon the
    "advertisement allowance" is a might higher than usual for Volcano
    brand. Do you think they might be using a peak-to-peak value?

    Lessee, OP said his Volcano drew 9.8Arms. 9.8 * 120 * 1.414 ~=
    1660Wpk, or 3320Wpp. Subtract 520Wpp (183Wrms, or ~1.5Arms) for the
    blower motor, and we may have arrived at the marketing genius behind
    the 2800W Volcano. Brilliant!
Ask a Question
Want to reply to this thread or ask your own question?
You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.
Electronics Point Logo
Continue to site
Quote of the day