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Determine voltage of a Christmas tree minibulb?

D

Dugie

Jan 1, 1970
0
Hi,

Using my multi-meter, is there any way to determine the voltage of a
working individual mini-bulb from a set for a Christmas tree? One set needs
2.5 v bulbs, another 3.5, another 6.

Thanks,
Dugie
 
H

hr(bob) [email protected]

Jan 1, 1970
0
Hi,

Using my multi-meter, is there any way to determine the voltage of a
working individual mini-bulb from a set for a Christmas tree? One set needs
2.5 v bulbs, another 3.5, another 6.

Thanks,
Dugie

Good question, complicated answer.

Start with a 2.5 V power supply, see how bright the light is, if it is
dim, try 3.5V and then 6V. But there is more to it than just the
voltage, there is also the current rating.

Even if there are 35 lamps in series across 120V, leading to a
conclusion of 3.5 V per bulb, different strings of 35 lamps may have
different currents. If you put a 3.5 V bulb from a low current string
into a string that has a higher current level, due to lower resistance
lamps, the 3.5V lamp will have too much current through it and light
up very brightly before burning out.

The only sure way to tell if a bulb is compatible with a particular
string of lights is to run the string of lights at half brightness or
lower, using a variac or lamp dimmer, put in the bulb in question, see
that it is equally as bright as the other lamps in the string, and
then increase the voltage gradually to make sure that the bulb in
questions stays the same brightness as the other bulbs in the
string.

Just measuring cold bulb resistance with a multimeter is not a very
reliable indication of the bulb as different bulbs have different
changes in resistance when they are heated to illumination levels.

H. R.(Bob) Hofmann
 
D

Dugie

Jan 1, 1970
0
Good question, complicated answer.

Start with a 2.5 V power supply, see how bright the light is, if it is
dim, try 3.5V and then 6V. But there is more to it than just the
voltage, there is also the current rating.

Even if there are 35 lamps in series across 120V, leading to a
conclusion of 3.5 V per bulb, different strings of 35 lamps may have
different currents. If you put a 3.5 V bulb from a low current string
into a string that has a higher current level, due to lower resistance
lamps, the 3.5V lamp will have too much current through it and light
up very brightly before burning out.

The only sure way to tell if a bulb is compatible with a particular
string of lights is to run the string of lights at half brightness or
lower, using a variac or lamp dimmer, put in the bulb in question, see
that it is equally as bright as the other lamps in the string, and
then increase the voltage gradually to make sure that the bulb in
questions stays the same brightness as the other bulbs in the
string.

Just measuring cold bulb resistance with a multimeter is not a very
reliable indication of the bulb as different bulbs have different
changes in resistance when they are heated to illumination levels.

H. R.(Bob) Hofmann

Very complicated. Thank you, Bob.
I forget to write: 250 lamps, "straight line" (meaning the same as in series?), 110/120v AC. I don't think I am motivated to try your innovative dimmer solution, but it's close. Sounds almost like fun. :)
The math for 250 lamps of 2.5 volts across 120v doesn't seem to work out either.

Dugie

Note: for YOUR message only, my replies aren't indented with >. I inserted them manually. As a test, any other messages I replied to have the ">"
 
C

Chuck

Jan 1, 1970
0
Good question, complicated answer.

Start with a 2.5 V power supply, see how bright the light is, if it is
dim, try 3.5V and then 6V. But there is more to it than just the
voltage, there is also the current rating.

Even if there are 35 lamps in series across 120V, leading to a
conclusion of 3.5 V per bulb, different strings of 35 lamps may have
different currents. If you put a 3.5 V bulb from a low current string
into a string that has a higher current level, due to lower resistance
lamps, the 3.5V lamp will have too much current through it and light
up very brightly before burning out.

The only sure way to tell if a bulb is compatible with a particular
string of lights is to run the string of lights at half brightness or
lower, using a variac or lamp dimmer, put in the bulb in question, see
that it is equally as bright as the other lamps in the string, and
then increase the voltage gradually to make sure that the bulb in
questions stays the same brightness as the other bulbs in the
string.

Just measuring cold bulb resistance with a multimeter is not a very
reliable indication of the bulb as different bulbs have different
changes in resistance when they are heated to illumination levels.

H. R.(Bob) Hofmann

Very complicated. Thank you, Bob.
I forget to write: 250 lamps, "straight line" (meaning the same as in
series?), 110/120v AC. I don't think I am motivated to try your innovative
dimmer solution, but it's close. Sounds almost like fun. :)
The math for 250 lamps of 2.5 volts across 120v doesn't seem to work out
either.

Most likely the bulbs are in series strings of 50 2.5V bulbs. The 5 strings
are very likely in parallel. This is how they set them up. This is how the
math works. Is it one long string with a single AC power plug?
 
R

Ray

Jan 1, 1970
0
Just count the number of bulbs that go out when you remove a bulb from a
working string...
then divide 120 volts (if in North America) by the number of bulbs in each
section,

10 bulbs would be 12 volt bulbs
20 bulbs would be 6 volt bulbs
50 bulbs or so would be 2.5 volt bulbs
These are nominal voltages, Some strings use a few more bulbs and run not
as bright.
 
C

Chuck

Jan 1, 1970
0
Ray said:
Just count the number of bulbs that go out when you remove a bulb from a
working string...
then divide 120 volts (if in North America) by the number of bulbs in
each section,

10 bulbs would be 12 volt bulbs
20 bulbs would be 6 volt bulbs
50 bulbs or so would be 2.5 volt bulbs
These are nominal voltages, Some strings use a few more bulbs and run not
as bright.

Now that was a good common-sense troubleshooting response. Right to the
point. Excellent!
 
B

Bill Jeffrey

Jan 1, 1970
0
Chuck said:
Now that was a good common-sense troubleshooting response. Right to the
point. Excellent!

Good answer, but that wasn't his question. If I read the OP correctly,
he has a bulb in his hand (not in a string) and doesn't know which
string it goes into. In other words, he doesn't know how many volts it
takes to light this particular bulb.

Bill
 
R

Ray

Jan 1, 1970
0
Bill Jeffrey said:
Good answer, but that wasn't his question. If I read the OP correctly, he
has a bulb in his hand (not in a string) and doesn't know which string it
goes into. In other words, he doesn't know how many volts it takes to
light this particular bulb.

Bill
Just using a multimeter is not a practical approach..

It is hard to make contact with those tiny wires, which probably have
corrosion on them, and so make resistance readings erratic

You would have to make a test socket to make a good connection for an
ohmmeter, or use a variable power supply power supply light the bulb
individually.

The post mentioned many different strings, so I assume the guy just wants to
get his lites working,

something which I just finished doing.

Also save the old bulbs to use the bases, as new bulb bases are not always
supplied, or dont fit properly if they are supplied.
 
M

mike

Jan 1, 1970
0
Bill said:
Good answer, but that wasn't his question. If I read the OP correctly,
he has a bulb in his hand (not in a string) and doesn't know which
string it goes into. In other words, he doesn't know how many volts it
takes to light this particular bulb.

Bill
This is NOT brain surgery.
Take the unknown bulb. Remove a bulb from one of the target strings.
Hook them in series accross a voltage source. Turn up the volts
till they light at normal brightness. If they're the same brightness,
you've found a match.
If you want to use the multimeter, measure the voltage across each bulb.
If equal, they match. If not, try a bulb from another target string...
mike
 
J

James Sweet

Jan 1, 1970
0
Bill Jeffrey said:
Good answer, but that wasn't his question. If I read the OP correctly, he
has a bulb in his hand (not in a string) and doesn't know which string it
goes into. In other words, he doesn't know how many volts it takes to
light this particular bulb.

Just put it in a string and see what it does. Most are either 2.5 or 3.5V,
with older ones being 6V. Even if you put a 2.5V bulb in a 6V string, it
will not usually blow instantly, you can tell if the brightness is way off
if it's wrong.
 
Just put it in a string and see what it does. Most are either 2.5 or 3.5V,
with older ones being 6V. Even if you put a 2.5V bulb in a 6V string, it
will not usually blow instantly, you can tell if the brightness is way off
if it's wrong.- Hide quoted text -

- Show quoted text -

That's why I suggested starting out with the string of lamps/bulbs
plugged into a lamp dimmer switch, like you would use on any
incandescent light. I have burned out a few bulbs trying your method,
when pluged into a full 120V circuit.

Bob H
 
D

Dugie

Jan 1, 1970
0
Bill Jeffrey said:
Good answer, but that wasn't his question. If I read the OP correctly,
he has a bulb in his hand (not in a string) and doesn't know which
string it goes into. In other words, he doesn't know how many volts it
takes to light this particular bulb.

Bill

Bill, you're right, and thanks: I have a bulb in my hand, and want to know the proper voltage it requires.

I have measured resistance, and get a reading of 1 (full resistance) for a burnt bulb.

Working bulbs have varying resistance, depending on voltage, I guess. My meter is set at 200 on the OHM scale (selections from 2000K to 200).
Results:
1.7 or 1.6 for bulb from the 2.5v set
3.5 for unknown volt bulb
2.2 " " " "
and
20.2 for a motorized ornament of unmarked voltage which plugs into a socket of the 2.5v set.
This last may be either bad or good for the other bulbs; if the motor draws more or less voltage. My guess is it draws less voltage, thus is bad for the other bulbs.

The other info is interesting, too, i.e. Ray's idea. And I now understand why not replacing burnt bulbs is hard on the working bulbs - they receive more voltage, burn brighter, and thus burn out faster... if I infer correctly.

Thank you all. This group is great, and has also helped me before.

Dugie
 
D

Dugie

Jan 1, 1970
0
Chuck said:
Very complicated. Thank you, Bob.
I forget to write: 250 lamps, "straight line" (meaning the same as in
series?), 110/120v AC. I don't think I am motivated to try your innovative
dimmer solution, but it's close. Sounds almost like fun. :)
The math for 250 lamps of 2.5 volts across 120v doesn't seem to work out
either.

Most likely the bulbs are in series strings of 50 2.5V bulbs. The 5 strings
are very likely in parallel. This is how they set them up. This is how the
math works. Is it one long string with a single AC power plug?

It is seemingly "one long string" with one AC power plug, but some parts have say 4 or 5 wires twined together, so as you write, it's 5 parallel strings.

I'd like to extend the wires of a bulb enough to be able to measure the working voltage with the set on. Now, if I measure the AC current in an empty socket, with the probes completing the circuit, I get a reading of about 135 volts. I'll use alligator clips to avoid the shock of learning. :)

Dugie
 
C

Chuck

Jan 1, 1970
0
Bill Jeffrey said:
Good answer, but that wasn't his question. If I read the OP correctly,
he has a bulb in his hand (not in a string) and doesn't know which
string it goes into. In other words, he doesn't know how many volts it
takes to light this particular bulb.

Bill

Bill, you're right, and thanks: I have a bulb in my hand, and want to know
the proper voltage it requires.

I have measured resistance, and get a reading of 1 (full resistance) for a
burnt bulb.

Working bulbs have varying resistance, depending on voltage, I guess. My
meter is set at 200 on the OHM scale (selections from 2000K to 200).
Results:
1.7 or 1.6 for bulb from the 2.5v set
3.5 for unknown volt bulb
2.2 " " " "
and
20.2 for a motorized ornament of unmarked voltage which plugs into a socket
of the 2.5v set.
This last may be either bad or good for the other bulbs; if the motor
draws more or less voltage. My guess is it draws less voltage, thus is bad
for the other bulbs.

The other info is interesting, too, i.e. Ray's idea. And I now understand
why not replacing burnt bulbs is hard on the working bulbs - they receive
more voltage, burn brighter, and thus burn out faster... if I infer
correctly.

Thank you all. This group is great, and has also helped me before.

Dugie

There are "shunts" in the bulbs that act like shorts to pass on the voltage
if a filament burns out. The shunts are flaky and that is why you are
getting different Ohm readings with a meter. Bulbs are cheap and there are
only a few voltages available. If you want to go to the trouble you can
wire the strings up to a dimmer switch and bring the intensity up gradually
until its acceptable. And yes... in theory less working bulbs means a
higher voltage to all remaining bulbs, but in a huge string like you have it
would be negligible and spreadout between them all. You only have two days
left until Santa arrives...
 
J

James Sweet

Jan 1, 1970
0
It is seemingly "one long string" with one AC power plug, but some parts
have say 4 or 5 wires twined together, so as you write, it's 5 parallel

'd like to extend the wires of a bulb enough to be able to measure the
working voltage with the set on. Now, if I measure the AC current in an
about 135 volts. I'll use alligator clips to avoid the shock of learning.
:)


It's just simple math. 5 segments of 20 lamps making a 100 lamp string, this
is common. Each segment is 120V across 20 lamps, so 6V lamps. The other
common arrangement is two sections of 50 lamps each, with 2.5V lamps.
 
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