J
John Larkin
- Jan 1, 1970
- 0
It does? Maybe since you defined Vr=Vs-Vx and hide it from yourself it
seems that way, but Vs is still there....
It's there, but doesn't afect the results as long as it's short-term
stable. Of course, you *do* have to accept Ohm's Law for the duration.
I assumed that a pic would only digitize ground-referenced voltages,
hence the path through the math. When I do this, I usually use a fully
differential adc, so I can measure the voltage across each resistor
directly, which has the advantage of ignoring any lead resistances.
John