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DC Wave Questions

K

Kevin Aylward

Jan 1, 1970
0
But what if the "capacitance" present is actually a property of
something other than a part sold as a "capacitor"?

Well, that's ok. To say "there is a capacitance in the circuit", would
mean that there is the property of capacitance, irrespective of whether
or not there was an explicit capacitor present.

Kevin Aylward
[email protected]
http://www.anasoft.co.uk
SuperSpice, a very affordable Mixed-Mode
Windows Simulator with Schematic Capture,
Waveform Display, FFT's and Filter Design.
 
K

Kevin Aylward

Jan 1, 1970
0
ehsjr said:
Kevin,

I'm glad you know what people *really* mean. :) However, you
*really* do need to read the relevant posts again.
Here's the context:



Saturation was overlooked. Case closed.

Well, I suppose I will have to qualify that with "those that really know
what they are doing"

Its so obvious to pros that inductors might well saturate, that they
simply wont address that issue when responding to basic electrical
questions on AC and DC analysis. You can't qualify everything one says.
One has to assume something to avoid reams of verbiage.

Kevin Aylward
[email protected]
http://www.anasoft.co.uk
SuperSpice, a very affordable Mixed-Mode
Windows Simulator with Schematic Capture,
Waveform Display, FFT's and Filter Design.
 
T

Tom Grayson

Jan 1, 1970
0
Hey JackBruce
I got fed up with the crap the other posters wrote about your terminology,
and did not really see if anyone actually answered your question, Which, by
the way, Was very easy to understand. Ignore the other jackasses here, that
nitpick. They have too much time on their hands, i can see.

Question 1
The impedance of inductors and reactors is based on the varying signal
frequency, Weather it is offset by the DC component or not.
This answer assumes that you are not reaching the current limit of any of
the devices, naturally if the DC Current in the "L" Device saturates the
Flux medium ( air or iron) then you will get non linearities introduced,
Not sure what the limit on a "C" Device would be, probably current again.

Question 2
The link didn't work but most of the modern devices looking for peaks and
valleys work fine with a DC Offset.

Tom Grayson
 
D

Danny

Jan 1, 1970
0
I've just noticed this 'long' thread. It is of interest to me as I had
a not dissimilar problem. The use of superposition is absolutely
correct in a linear system where the system component values do not
vary with the signal applies. However, when applying the ac component
the skin effect phenomenon will deplete the current carrying carriers
from the centre of the conductive component thus reducing the effective
cross sectional area......which will also effect the dc
resistance....or will it?

Danny
 
R

Reg Edwards

Jan 1, 1970
0
Danny said:
I've just noticed this 'long' thread. It is of interest to me as I had
a not dissimilar problem. The use of superposition is absolutely
correct in a linear system where the system component values do not
vary with the signal applies. However, when applying the ac component
the skin effect phenomenon will deplete the current carrying carriers
from the centre of the conductive component thus reducing the effective
cross sectional area......which will also effect the dc
resistance....or will it?

Danny

========================================

No, it won't. However, it does appear have affected superposition of
your thinking processes. ;o)
 
G

Guest

Jan 1, 1970
0
I've just noticed this 'long' thread. It is of interest to me as I had
a not dissimilar problem. The use of superposition is absolutely
correct in a linear system where the system component values do not
vary with the signal applies. However, when applying the ac component
the skin effect phenomenon will deplete the current carrying carriers
from the centre of the conductive component thus reducing the effective
cross sectional area......which will also effect the dc
resistance....or will it?

Danny
It will not. Each frequency component will work independently of others.
The modification of resistance by heating is a nonlinear effect that will
couple different frequencies.

Bill
 
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