Thank you for answering. I've experimented around a bit and it seems that when you are just using a resistor, you do need to choose its value to get somewhere in the neighborhood of 12mA or so for good volume; but when you throw in the capacitor, that doesn't seem to be the case. For example, with a 1000 ohm resistor combined with a 470microfaradt capacitor, you get around a 6.3-6.5mA current at 9V and it works... Without the capacitor you get about half that and it doesn't work so well. The voltage drops shift too (which is to be expected). We go from 3.16v across the resistor and 5.8 across the buzzer with no capacitor to 6.51 across the resistor and 2.42 across the buzzer. It's almost as if the buzzer has a resistance of its own that varies depending on your voltage, R1 value, and whether or not you are running a capacitor parallel to it. That doesn't really make any sense and I'm pretty sure you are right about the charging and discharging - but it doesn't seem they are discrete events - except when you first close the circuit and then when you open it again... If you let the buzzer ring for an extended period of time, it doesn't seem that the capacitor cycles between charging and discharging as discrete events. It seems like they would be happening at the same time, eventually coming to an equilibrium of sorts... I guess I'm looking for some insight into the math behind all this if that makes sense, but I can't quite get at it.... Thanks again.