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Curent Fed Inverter / Voltage Fed inverter

Discussion in 'Electronic Basics' started by srg, Mar 11, 2006.

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  1. srg

    srg Guest

    Dear Group,

    Could someone please kindly explain the topology of current fed inverters.
    I wish to drive a parallel tank circuit with the out put of the inverter.
    What I do not understand is the topology of the source circuit ie :-
    As I understand it ---
    A voltage fed inverter users a 240 AC line into a bridge rectifier which
    converts to DC that is then fed to a cap for smoothing which then supplies
    the inverter.
    A current fed inverter users a 240v AC line into a bridge rectifier which
    converts to DC that is then fed to an inductor in series which then supplies
    the inverter.
    How does one calculate the value for the inductor?

  2. Paul Mathews

    Paul Mathews Guest

    When you switch the power stage of a switchmode converter, something
    has to limit the current into the output capacitors. Normally, an
    inductance does the job. You can have inductance on the primary side,
    on the secondary side, or both. When you put the inductance mostly on
    the primary side, this is called "current fed". One way to calculate
    the desired inductance: for the lowest voltage across the inductor
    (i.e., low line conditions) and the longest allowable switching
    interval (on-time), the inductance should not limit the change of
    current to less than what is required to deliver rated power through
    the converter:

    V = L di/dt

    A vague answer for a vague question.

    Paul Mathews
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