J
Joe G \(Home\)
- Jan 1, 1970
- 0
Hi All,
I am hope some can confirm statements below.
For a capacitor
Q = C * V = I * t
I am trying to work out how long an electrolytic will hold up the Vdd on
circuit.
nominal Vdd = 3.3v and lowest Vdd = 2.4v
If the current drawn by the circuit is constant 10mA = I
C * V = I * t
Thus t (time) = (C * V) / I Where V = 3.3v - 2.4v =
0.9 v
Hence for a 10,000uF the time the Vdd rail is held up is
t(time) = (10,000 E-6 * 0.9) / 0.01 = 900mS
QUESTIONS
Q1
Are my statements above correct?
Q2
Should I use the natural e discharge model V = 3.3v * (1 - e(t))
style of equation?
any ideas on this equation would be appreciated.
Joe
I am hope some can confirm statements below.
For a capacitor
Q = C * V = I * t
I am trying to work out how long an electrolytic will hold up the Vdd on
circuit.
nominal Vdd = 3.3v and lowest Vdd = 2.4v
If the current drawn by the circuit is constant 10mA = I
C * V = I * t
Thus t (time) = (C * V) / I Where V = 3.3v - 2.4v =
0.9 v
Hence for a 10,000uF the time the Vdd rail is held up is
t(time) = (10,000 E-6 * 0.9) / 0.01 = 900mS
QUESTIONS
Q1
Are my statements above correct?
Q2
Should I use the natural e discharge model V = 3.3v * (1 - e(t))
style of equation?
any ideas on this equation would be appreciated.
Joe