# Counter 6-5-4-3-6-5-4-3... with D flips flops.

Discussion in 'General Electronics Discussion' started by MidnightRider, Apr 27, 2013.

1. ### MidnightRider

3
0
Feb 24, 2013
How to make a Counter with 6-5-4-3-6-5-4-3 sequence using D flip-flops.

2. ### (*steve*)¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥdModerator

25,496
2,837
Jan 21, 2010
Can you explain further?

Is the output to be binary? Or can we choose our own encoding scheme?

What is the purpose for this (perhaps we can suggest a better way)?

To ask the question in this way sounds almost as if it is homework.

3. ### Laplace

1,252
184
Apr 4, 2010
Here is how to make a counter using D flip-flops: Identify some number of flip-flops to comprise the counter. Each FF will have a Q output and a D input. Construct a next-state truth table with Q0...QN as inputs and D0...DN as outputs. For any state of Q0...QN, D0...DN will represent the next state of Q0...QN (after the next clock pulse). Using the truth table, construct a Karnaugh Map for each Dn. Minimize the map and design the gate structure for each Dn input. You have a counter!

4. ### Raven Luni

798
8
Oct 15, 2011
A count is a count. Its only the interpretation that matters - 0=6, 1=5, 2=4, 3=3