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Clipper and Clamper Help

Discussion in 'Electronic Basics' started by Kartik Aiyer, Jul 2, 2004.

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  1. Kartik Aiyer

    Kartik Aiyer Guest

    Need some help trying to figure this out

    Consider a clipper circuit with only one diode.

    -----Res-------------
    | +
    + D (+)
    Vi i (-) Vo
    - |
    |
    D (+ Vb) -
    C (-)
    ----------------------

    I am sorry but its the best I could do. So Di is a diode (Vt cut it
    Voltage) and DC is a dc source (Vb). Now i believe the diode stays
    off when Vi < Vb+Vt
    and the output follows the input. (Res is a resistor R)

    When Vi> Vb+ Vt the diode turns on and the Vo is clipped at Vb+Vt.

    I dont understand why the diode is off when Vi<Vb+Vt ( i cant figure
    what the voltage is across the diode) and why the diode is on when Vi
    Also in a clamper circuit with one capacitor and one diode, when we
    use an AC sinusoidal input, I understand that on the rising of the
    signal the output voltage (measured across the diode) follows the
    input (assuming zero forward resistance on the diode). Why is it when
    the signal begins to decrease the diode is reverse biased.

    I would appreciate any help whatsoever.
     
  2. dB

    dB Guest



    Are you sure that you understand diodes?
     
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