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Cartridge Heater Circuit Burnt

Discussion in 'General Electronics Discussion' started by Kogarona, May 13, 2014.

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  1. Kogarona

    Kogarona

    1
    0
    May 13, 2014
    Hello
    I had a machine that heats up air with a 110v 40w ceramic cartridge but one of the resistances of the circuit board burned itself and now the machine isn't working. My initial idea was to try to find the value of the burnt resistor and replace it but as it is completely burnt I cannot see the color code on it.

    I tried redrawing the circuit board for you guys but I don't know if it's correct... I tried my best

    So what do you recommend... can anybody help me with the value of the resistor...
    Or how can I make it work again?
    The board is controlled by a digital display wich turns on and increases and decreases the temperature

    IMG_20140512_202615.jpg IMG_20140512_202631.jpg IMG_20140512_202639.jpg IMG_20140512_202650.jpg IMG_20140512_202700.jpg IMG_20140512_202708.jpg IMG_20140512_202728.jpg IMG_20140512_204841.jpg Thank you all!
     
  2. shrtrnd

    shrtrnd

    3,761
    484
    Jan 15, 2010
    Did the burned resistor burn itself 'open circuit', or can you read a value across it with an ohmeter? That might at least get you in the ball-park for a replacement.
    You're bound to have other damage on the board due to the excessive current through the burned resistor circuit. Do you have an ohmeter to check the resistances
    found on the other components on the board?
     
  3. MicroMe

    MicroMe

    17
    0
    May 18, 2014
    I can't work out the circuit but I think your burnt out resistor is a voltage dropper for the 5V regulator circuit, so I'm assuming the resistor and 1N4007 is the supply to the regulator. As shrtnd states there is a high chance of damage to other components such as the regulator and anything else on that supply, BUT you could be lucky and the resistor just burnt out.
    I pressume there is more circuitry connected to the plug at the top of this board and that could be at fault as well.

    WARNING. This is a non-isolated circuit so it is all potentially at mains voltage.

    If I can think of anyway of testing the board without the mains applied I'll post again.
     
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