I'm still trying to get my head round the simple stuff.
This circuit: http://archilochus.netfirms.com/images/q_timer.jpg am I understanding it correctly?
The current runs through the diode and, as the path through the capacitor gives less resistance (and as the transistor is 'open'), through the capacitor which charges to its nominal value.
This is where I'm stuck. What causes the capacitor to drain? As it's fully charged has it become more resistant than the resistor?
I'll have to build this later. But first, I think I need someone to state the plain obvious so that I can understand.
This circuit: http://archilochus.netfirms.com/images/q_timer.jpg am I understanding it correctly?
The current runs through the diode and, as the path through the capacitor gives less resistance (and as the transistor is 'open'), through the capacitor which charges to its nominal value.
This is where I'm stuck. What causes the capacitor to drain? As it's fully charged has it become more resistant than the resistor?
I'll have to build this later. But first, I think I need someone to state the plain obvious so that I can understand.