R
ray13
- Jan 1, 1970
- 0
Power equals (voltage squared) divided by resistance. P=E*E/R
M.Joshi said:Hello,
I was wondering if there is a method of calculating the value and
wattage for the resistor that goes across a mains capacitor to
discharge it once the power has been removed?
M.Joshi said:Hello,
I was wondering if there is a method of calculating the value and
wattage for the resistor that goes across a mains capacitor to
discharge it once the power has been removed?
Arfa said:Any cap that is placed across the mains in a piece of equipment,
should not in theory require any resistor to discharge it, since the
load presented by the equipment itself should do that. The value of
any such caps is usually very small anyway, so any residual charge
from the last half cycle of the mains that appeared across it, will
be more or less *instantaneously* discharged by the load.
Arfa
TimPerry said:Arfa, some of the equipment i work on used high voltage supplies to power
tubs power amplifiers. large bleeder resistors are place across the HV
filter capacitor in the event of a tube failure (or some other type of
failure) that would leave a HV cap charged up.
these are often 100 k ohm 200 watt wirewound placed in series/parallel.
the
ides is to discharge 7,300 volts in about two or three seconds down to a
"safe" level (at least safe enough to open the doors without a giant arc
when the safety shunts engage.
other units switch the bleeders in when the doors open.
M.Joshi, the resistance is set by taking the voltage and capacitance into
consideration and deciding how fast you want to discharge the cap. then
wattage is determined by E max squared / R then multiply by whatever
safety
factor you feel comfortable with and round off to the nearest standard
value.
here's a place to read about time constants.
http://www.kpsec.freeuk.com/capacit.htm
M.Joshi said:Hi Arfa,
You are spot-on, I am referring to the capacitor across the
mains/supply (Usually termed X-type).
We have a kitchen appliance (Moulinex - I think) which has a motor and
is connected by a switch which automatically disconnects when you stop
using the machine.
I have found that if the plug is removed, you get a small
electric-shock if you accidently touch the live & neutral pins. I
tested this by plugging the appliance into the mains socket, then
removing the plug and shorting the two pins together. You can see and
hear a small spark!
I am assuming that either the appliance has a faulty resistor
connected across the supply capacitor or they failed to include one at
manufacture?
M.Joshi said:Hi Arfa,
You are spot-on, I am referring to the capacitor across the
mains/supply (Usually termed X-type).
We have a kitchen appliance (Moulinex - I think) which has a motor and
is connected by a switch which automatically disconnects when you stop
using the machine.
I have found that if the plug is removed, you get a small
electric-shock if you accidently touch the live & neutral pins. I
tested this by plugging the appliance into the mains socket, then
removing the plug and shorting the two pins together. You can see and
hear a small spark!
I am assuming that either the appliance has a faulty resistor connected
across the supply capacitor or they failed to include one at
manufacture?
M.Joshi said:Having opened up the appliance, I discovered that there is an X2 0.1µF
275V interference suppression capacitor across the supply which has no
load present when the appliance is in idle mode. Hence, the capacitor
remains charged when the plug is removed.
I'm sure I have seen resistors across X2 capacitors in-circuit usually
in the Mega-Ohm range?
Looking at the Maplin metal film 2W resistors, they can handle 500V.