Calculate current in shunt resistor

Discussion in 'Electronics Homework Help' started by inlineskater, Jun 15, 2012.

1. inlineskater

13
0
Jun 15, 2012
Ok using the following:

Ish/Im = Rm/Rsh

Rsh = shunt resistance
Rm = meter resistance
Ish = shunt current
Im = meter current

A moving coil ammeter has a coil resistance of 28.5 ohms and a shunt resistor of 1.6 ohms. When the 0-740 mA display reads it maximum, how much current flows through the shunt resistor?

I need help on this. I have tried with calculating the voltage and power ... help

2. CocaCola

3,635
5
Apr 7, 2012
Homework?

If so show your work and answers and someone will hopefully guide you from there...

3. Laplace

1,252
184
Apr 4, 2010
You have one equation and two unkown variables. What is the second equation?

4. john monks

693
2
Mar 9, 2012
This is not as much a mathematics problem as it is science problem. This is exactly why you should not be in trapped by memorizing formulas. You should be deriving all your formulas from definitions and scientific facts. If you cannot derive a formula you shouldn't be using it. Without looking at a formula tell me what happens when you apply a current to two resistances in parallel.

5. inlineskater

13
0
Jun 15, 2012
Solved

Hello

This is a math problem and it needed to be rearranged. I did it!

I(sh) = (( Rm / Rs + Rm)). IT

IT= Total current

Last edited: Jun 16, 2012
6. john monks

693
2
Mar 9, 2012
Sorry, I think you're missing the point. If all is you want is the answer you can do it using a formula. There are virtually an infinite number of combinations of parts and many types of parts involving inductors, capacitors, transistors, chemical batteries, and so forth, not just resistors. So are you going to memorize different formulas for all these different situations? Memorizing formulas is backwards. You must first understand the physics or the science and then wrap formulas around them. And if you do not understand how a resistor works get a resistor, a battery, and a multimeter and experiment with them. I design circuits for a living. I only rely on what I know about parts and data sheets. I see formulas on data sheets and I do not use them. I wrap my own numbers around the circuits based on what i know. If i relied only on formulas i never would be able to do my job. When I looked at your problem I realized instantly that you lacked understanding of the parts. So I say again that if you don't understand formula and you cannot derive if based on scientific fasts you should not be using it.

7. inlineskater

13
0
Jun 15, 2012
No point was missed.

Thanks

8. inlineskater

13
0
Jun 15, 2012
Good Point and point taken, next time I will do a complete update to the problem. I was working from a mobile location while being on set.

Thanks

9. inlineskater

13
0
Jun 15, 2012
One equation and 2 variable. The expression needed to be arranged as posted. Next time around I shall post all the steps I have taken to solve for the unknown.

Thank you

10. Laplace

1,252
184
Apr 4, 2010
From the wording of the question I can't tell whether the second equation should be (Im=740 mA) or (Im+Ish=740 mA).

11. weird_dave

36
0
May 9, 2012
Edited because I was being daft.

It's not obvious if the meter is 740mA with the shunt in place or if that's the 'standalone' reading without a shunt.

Last edited: Jun 17, 2012