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C- reading in a character

foTONICS

Sep 30, 2011
332
Joined
Sep 30, 2011
Messages
332
Hey all,

I'm working on a lab for programming and have run into a hiccup. Below is a sample of my code (edited for clarity):

#include <stdio.h>
#include <stdlib.h>

char d;

int main (void)
{
printf("*\t\tCharacter Arithmetic\n");
printf("***************************************************\n");
printf("* Please select one of the following options\n");
printf("* Followed by the proper response\n");
printf("***************************************************\n");
printf("* Functions:\n");
printf("* a. isDigit\n");
printf("* b. isLetter\n");
printf("* c. toUpper\n");
printf("* d. toLower\n");
printf("* q. Quit\n");
printf("***************************************************\n");
printf(" CHOOSE A FUNCTION: ");
char f=getchar();
system ("cls");

switch (f)
{
case 'a':
printf("Please enter a digit:");
scanf("%c", &d);
printf("you entered %c", d);
system("PAUSE");
}
}


my problem is that after i choose my function, in this example 'a', my program doesnt wait for me to enter a digit, it skips the scanf command and just jumps straight to the second printf statement in my switch statement.

any guidance would be appreciated
 

foTONICS

Sep 30, 2011
332
Joined
Sep 30, 2011
Messages
332
okay so i scanned in the character 'd' as a integer (%d) instead of %c, and its somewhat working, any reasoning behind this?

ASCII?
 
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