I am building an EMP out of a 330V 120uF disposable camera capacitor. I am using a R13-423L2 LED toggle switch for my On/Off switch. The switch has three leads, Power, Acc, and Ground, and the Ground lead has a 680 Ohm resistor attached(http://www.rapidonline.com/pdf/75-0378.pdf).
I soldered a copper wire to the positive end of the capacitor and wrapped the wire around a 12" diameter cardboard tube 25 times, afterward connecting this wire to the Power lead on my switch. Then, I soldered another copper wire from the Ground lead on my switch to the negative end of my capacitor.
I placed a cheap calculator next to my device, charged the capacitor, and turned it on. The LED on the toggle switch turned on, but the calculator still worked. I did a calculation, and given the 680 Ohm resistor and 330V/120uF capacitor, the current is only .485 Amps, which resulted in a B field of .3 mT, way too low.
I redid the calculation, this time using the resistance of the copper wire(I figured the current flowing through the wire before it reached the resistor would also be generating a B field). The copper wire I am using is rated at .00751 Ohm/ft, and this resulted in a current of 1700-1800 Amps, a B field of about 1.1 T, powerful enough to use as an EMP. Obviously, this calculation is not representing reality.
My question is, what did I do wrong, and how can I do this correctly? Should I buy a switch with less resistance? Or did I just wire my device incorrectly?
Thank you for your time and thank you for any advice you may have for me.
EDIT: I am convinced that the 680 Ohm resistor on the switch is the limiting factor, will update again once I test with a lower resistance switch.
I soldered a copper wire to the positive end of the capacitor and wrapped the wire around a 12" diameter cardboard tube 25 times, afterward connecting this wire to the Power lead on my switch. Then, I soldered another copper wire from the Ground lead on my switch to the negative end of my capacitor.
I placed a cheap calculator next to my device, charged the capacitor, and turned it on. The LED on the toggle switch turned on, but the calculator still worked. I did a calculation, and given the 680 Ohm resistor and 330V/120uF capacitor, the current is only .485 Amps, which resulted in a B field of .3 mT, way too low.
I redid the calculation, this time using the resistance of the copper wire(I figured the current flowing through the wire before it reached the resistor would also be generating a B field). The copper wire I am using is rated at .00751 Ohm/ft, and this resulted in a current of 1700-1800 Amps, a B field of about 1.1 T, powerful enough to use as an EMP. Obviously, this calculation is not representing reality.
My question is, what did I do wrong, and how can I do this correctly? Should I buy a switch with less resistance? Or did I just wire my device incorrectly?
Thank you for your time and thank you for any advice you may have for me.
EDIT: I am convinced that the 680 Ohm resistor on the switch is the limiting factor, will update again once I test with a lower resistance switch.
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