I found this great resource on setting resistance and adjusting load, but I closed my laptop and lost the resource.
Setting the resistance I understand fully.
10% RULE-
1. SET RESISTANCE where the amperage is 10% of the LOAD
[current bleed]
where I is amps
IBleed =
I =(0.10)(9.1a)=.91ma ( remark from dummystruk "(0.10 is 10% and 9.1a is the load" )
[resistor bleed]
Where E is volts and
Where R is resistance
OHMS LAW-
RBleed = E / I = R
R = 3v / .00091a = 3297
Select a resistor near the RBleed value - R1 = 3300
(dummystruk OK to here)
Then it says to ---
select a resistor to maintain the voltage.
I1 = I2 + ILoad = [.91ma + 9.1ma] = 10ma = .010a
R2(10v-3v) / .010a = 700 ohms
I did it in my head the first time through... everything was great... then I did it again later, and I am missing the 700ohms every time....
What I am doing wrong... I don't know what I2 is...
Is I1 = 9.1ma and I2 = .91ma?
R2 is my new resistance that maintains voltage, 10v-3v is 7/.010a = 700 the New resistor that maintains voltage is R2 = 700ohms
wow it worked! I don't believe it!
I wonder what I was doing wrong!!!
So what this 10% RULE is about is creating a circuit that works under load and does not use up the voltage?
Setting the resistance I understand fully.
10% RULE-
1. SET RESISTANCE where the amperage is 10% of the LOAD
[current bleed]
where I is amps
IBleed =
I =(0.10)(9.1a)=.91ma ( remark from dummystruk "(0.10 is 10% and 9.1a is the load" )
[resistor bleed]
Where E is volts and
Where R is resistance
OHMS LAW-
RBleed = E / I = R
R = 3v / .00091a = 3297
Select a resistor near the RBleed value - R1 = 3300
(dummystruk OK to here)
Then it says to ---
select a resistor to maintain the voltage.
I1 = I2 + ILoad = [.91ma + 9.1ma] = 10ma = .010a
R2(10v-3v) / .010a = 700 ohms
I did it in my head the first time through... everything was great... then I did it again later, and I am missing the 700ohms every time....
What I am doing wrong... I don't know what I2 is...
Is I1 = 9.1ma and I2 = .91ma?
R2 is my new resistance that maintains voltage, 10v-3v is 7/.010a = 700 the New resistor that maintains voltage is R2 = 700ohms
wow it worked! I don't believe it!
I wonder what I was doing wrong!!!
So what this 10% RULE is about is creating a circuit that works under load and does not use up the voltage?