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Bit-resolution and Clipping?

D

Dick Pierce

Jan 1, 1970
0
Perhaps a simpler analogy would be that it represents rather more than
the dynamic range that you would experience if you were standing in
the New Mexico desert at midnight on a perfectly still night - and a
cruise missile exploded ten feet away........... :)

Sure, except that the cruise missle detonation is short by a
dozen orders of magnitude or so.
 
S

Stewart Pinkerton

Jan 1, 1970
0
Sure, except that the cruise missle detonation is short by a
dozen orders of magnitude or so.

OK, let's go for a nuclear warhead at 3 feet, and extend 'rather more'
to 'lots more'............

And it's just a joke, Dick, I know you'll get the old slipstick out
again! :)
 
N

normanstrong

Jan 1, 1970
0
Dave Platt said:
Several reasons. Noise is one.

All electronics generate noise. One type, known as "thermal" noise,
occurs any time you have a resistance - the amount of noise depends on
the resistance and the temperature. If you set the maximum output
voltage of your DAC to a useful standard level (e.g. 2 volts
peak-to-peak, as is fairly usual for CD players and other line-level
outputs), you'll find that the thermal noise generated by the
resistances in the DAC circuitry will be down in the 24-bit region.
If you try to resolve signals smaller than that, they'll be buried in
the noise.

To get technical about it, noise is not dependent on resistance--just
temperature and bandwidth.
It is indeed = kTB, where k is a constant.

Norm Strong
 
S

Stewart Pinkerton

Jan 1, 1970
0
To get technical about it, noise is not dependent on resistance--just
temperature and bandwidth.
It is indeed = kTB, where k is a constant.

To get even more technical, noise *voltage* certainly is dependent on
resistance, even if noise power isn't.
 
T

Tom

Jan 1, 1970
0
Radium said:
Can a wave file with stronger bit-resolution handle more decibels
w/out clipping than a wave file with weaker bit-resolution?

Wot - no Soundblaster statement?

Tom
 
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