Basic Electronics Q.

[Nael]

Hi, I have a question that is basic but confuses me.

If I have 8 drycells 1.5V each, connected in series-parallel (2 groups, 4 cells each group)

I understand that the total voltage will be 1.5x8
but what is the total current? Is it the sum of all the cells? or the sum of one group?

 

[kellys_eye]

No, the total voltage will be the sum of the individual 'legs' therefore 4 x 1.5V (twice). Each leg is therefore 6V

If each cell was rated at 1Ahr then each 'leg' would be 6V and 1Ahr but two legs in parallel would be 6V 2Ahr.

Voltages in series add (but recall you have some in parallel too) whilst current in parallel add.

 

[Nael]

No, the total voltage will be the sum of the individual 'legs' therefore 4 x 1.5V (twice). Each leg is therefore 6V

If each cell was rated at 1Ahr then each 'leg' would be 6V and 1Ahr but two legs in parallel would be 6V 2Ahr.

Voltages in series add (but recall you have some in parallel too) whilst current in parallel add.

Thank you, May I ask what do you mean by 'leg'?

 

[kellys_eye]

Your arrangement was described thus:

B1 - B2 - B3 - B4

B5 - B6 - B7 - B8

There are two 'legs' (B1 to B4) and (B5 to B8) i.e.

(2 groups, 4 cells each group)

B1 to B4 are in series therefore their battery voltages ADD (6V)

B5 to B8 are also in series (6V)

 

[Nael]

Your arrangement was described thus:

B1 - B2 - B3 - B4

B5 - B6 - B7 - B8

There are two 'legs' (B1 to B4) and (B5 to B8) i.e.


B1 to B4 are in series therefore their battery voltages ADD (6V)

B5 to B8 are also in series (6V)

Thank you so much cheeeeers