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Available Power?

Discussion in 'Electronic Components' started by Randy Gross, Aug 21, 2003.

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  1. Randy Gross

    Randy Gross Guest

    How much can I disclose?

    ____________________
    | _____ |_____
    120 vac ) || ( 8 vac |
    |
    60 HZ ) || ( R 1 R
    2
    6 A ) || ( 14 Ohms 21 Ohms
    50 Turns ) || ( 7 Turns |__________ |
    |___________________|

    From this schematic ( I hope it is readable ), I can determine R total as:

    1 / 14 + 1 / 21 = 1 / .119 = 8.4 Ohms. The current in this
    circuit is:

    I = 8 / 8.4 = 952 mA (800 mA actual reading).

    Question: From this data, can I determine the available current in the
    secondary?
    952 mA is the apparent current but, the actual available secondary current
    is much, much, higher.
     
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