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Available Power?

R

Randy Gross

Jan 1, 1970
0
How much can I disclose?

____________________
| _____ |_____
120 vac ) || ( 8 vac |
|
60 HZ ) || ( R 1 R
2
6 A ) || ( 14 Ohms 21 Ohms
50 Turns ) || ( 7 Turns |__________ |
|___________________|

From this schematic ( I hope it is readable ), I can determine R total as:

1 / 14 + 1 / 21 = 1 / .119 = 8.4 Ohms. The current in this
circuit is:

I = 8 / 8.4 = 952 mA (800 mA actual reading).

Question: From this data, can I determine the available current in the
secondary?
952 mA is the apparent current but, the actual available secondary current
is much, much, higher.
 
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