Array in ascending order

Hello

I am looking help to understand this program.

array in ascending order in C programming

Code:

#include <stdio.h>
 
int main(void)
{
    int a[20], i = 0, j = 0, n, t;
 
    printf ("\n Pramot user to Enter Element: ");
    scanf ("%d", &n);
    printf ("\n");
 
    for (i = 0; i < n; i++)
    {
        printf ("\n Enter the %dth element: ", (i+1));
        scanf ("%d", &a[i]);
    }
 
    for (j = 0 ; j <(n-1); j++)
    {
        for ( i = 0 ; i <(n-1) ; i++)
        {
            if (a[i+1] < a[i])
            {
                t = a[i];
                a[i] = a[i + 1];
                a[i + 1] = t;
            }
        }
    }
 
    printf ("\n Ascending order: ");
    for (i=0 ; i<n ; i++)
    {
        printf (" %d", a[i]);
    }
 
 
      return 0;
}

I don't understand this part of program

Code:

 
    for (j = 0 ; j <(n-1); j++)
    {
        for ( i = 0 ; i <(n-1) ; i++)
        {
            if (a[i+1] < a[i])
            {
                t = a[i];
                a[i] = a[i + 1];
                a[i + 1] = t;
            }
        }
    }

 

Yes I understand use of "for" loop

Code:

#include <stdio.h>
int main (void)
{
   int N = 10;
   int i; 
   for (i=0; i<N; i++)
   {
     printf ("Number %d \n",i);
   }
  
   return 0;
} 

Number 0
Number 1
Number 2
Number 3
Number 4
Number 5
Number 6
Number 7
Number 8
Number 9

 

It check the value n-1 value then print the value of j

Code:

#include <stdio.h>

int main()
{
   int j, n;
  
   printf("value of n : ");
   scanf("%d", &n);
  
   for (j = 0 ; j <n-1; j++)
          
    printf(" j : %d \n",j);
          
    return 0;
}

value of n : 4
j : 0
j : 1
j : 2

 

I was showing you that I understand what is "for (j = 0 ; j <(n-1); j++)"

I am stuck in three parts of the for statement. I don't know what is use of them ?

 

Where do you find wrong me in my understanding ?

Here loop run 5 times , first it set to 0 than increase by 1 until it get 4 and then stop

Code:

#include <stdio.h>

int main (void)
{
   int N = 5;
   int i;
   for (i=0; i < N; i++)
   {
     printf ("Number = %d \n",i);
   }
 
   return 0;
}

Number = 0
Number = 1
Number = 2
Number = 3
Number = 4

N-1 = 5-1 = 4
So N = 4
Here loop run 4 times , first it set to 0 than increase by 1 until it get 3 and then stop

Code:

#include <stdio.h>

int main (void)
{
   int N = 5;
   int i;
   for (i=0; i < N-1; i++)
   {
     printf ("Number = %d \n",i);
   }
 
   return 0;
}

Number = 0
Number = 1
Number = 2
Number = 3

 

I have make it simple

Code:

#include <stdio.h>
 int main(void)
{
    int a[10], i, j, n, temp;
 
    printf ("\n Pramot user to Enter size: ");
    scanf ("%d", &n);
   
      for (i = 0; i < n; i++)
      {
        printf ("\n Enter the  element: ");
        scanf ("%d", &a[i]);
      }
   
       for(i=0;i<n;i++)
      {
     
        for( j=i;j<n;j++)
        {
                if(a[i]>a[j])
                {
                        temp=a[i];
                        a[i]=a[j];
                        a[j]=temp;
                }
        }
       
      }
     
      for(i=0;i<n;i++)
             
      printf("%d ",a[i]);
   
 
      return 0;
}

Pramot user to Enter size: 4

Enter the element: 1

Enter the element: 9

Enter the element: 2

Enter the element: 5

1 2 5 9

 

I followed that link and wrote program in Post #11

 

Yes i understand how it works