answer this little question

[KUMARA SHP]

and briefly I want you to talk about :
Precision discussion either from manufacturer or through repeated
measurements which ever is applicable
•Results that can be determined without reference to predicted results
•Discussion of precision of data

like one sentence for each

Phase 1
Req = (1/R(1)+1/R(2))^-1
Req = ((1/5100)+(1/2200))^-1= 2109 ohms
Req = ((1/5100)+(1/10000)+(1/100000)= 3267 ohms

Phase 2
Determine the resistance of unknown resistor :
1st resistor
I= 0.4mA =0.0004A
Vs - (A)R -A(2200)=0
2.1V-(0.0004A)R-(0.0004*2200)=0
R= 3050 ohms
these are the sample calculation that I want you to do uncertainty for and error propagation
knowing the uncertainty for each resistor is +-5%

 

[KUMARA SHP]

please help me I need to do this by tomorrow, marks will be given to this

 

[Ian]

Hi Kumara,

Please check out the FAQ at the top of this forum section (https://www.electronicspoint.com/threads/please-read-homework-help-faq.219538/). We'll gladly provide help if you are stuck, but we're not going to do your homework for you.

Is there a particular bit that you're stuck on? Showing us how far you've got so far will help!

 

[davenn]

please help me I need to do this by tomorrow, marks will be given to this

you left it a bit late huh

follow Ian's instructions and if there is anyone that can guide you then hopefully they will do so

Dave

 

[KrisBlueNZ]

OK, your question is unclear and I suspect you don't have a clear understanding of what is being asked.

I've been trying to figure out what the question is about. This is what I think.

Phase 1 and Table 1 relate to two or three resistors in parallel, connected across a 2.1V voltage source. The current flow is measured.

The theoretial R_EQ (equivalent resistance of the paralleled resistors) is calculated using the standard formula for paralleled resistors, then the actual resistance is calculated from the applied voltage and the measured current, using Ohm's Law. This value is the "experiment" value at the right of Table 1.

There is a difference between the calculated value and the measured value. This is due to value errors in the resistance due to their tolerance, which is given as ±5%.

Phase 2 and Table 2, I'm not sure about. The first line makes sense if there is a black box that contains a voltage source, a current meter, and an "internal" series resistor of 2200Ω, and the test resistor is connected to the box. The current reading is recorded, and from this reading, you can calculate the external resistor. (There is also a voltmeter involved somehow, but the value given doesn't make sense.)

But the second line doesn't fit with that idea. So I don't know what the circuit configuration is.

Can you explain or, preferably, draw the circuit that relates to Table 2?

I don't know what your first three bullet points mean. The last line about uncertainty and error propagation probably refers to how the tolerance of the individual resistors (all resistors are ±5%) "propagates" and affects the combined resistance when resistors are connected in parallel and series.

Can you explain the question properly? If so, I might have a chance at guiding you towards an answer.