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- Jan 1, 1970
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NREL says 800 Btu/ft^2 of sun (300 diffuse) falls on a south wall on
an average 31.8 F December day with a 24.4 and 39.2 daily max and min
in Allentown, near the PA Renewable Energy Festival, 9/22-23/07,
http://www.paenergyfest.com, where I'll be talking about the system
below at 2:30 on Saturday and Nathan Hurst will talk about his Mazda
radiator solar heating experiments in Australia at 3:30 on Sunday.
Rich Komp (author of Practical Photovoltaics) will discuss energy-efficient
food storage at 3:30 on Saturday and new PV developments at 4:30 on Sunday.
We will all be exhibiting ourselves and a $35 1995 Mitsubishi 2.0 Eclipse
radiator at an "Ask the Engineer" table near Booth 24 in the exhibit area.
If a house is 65 F on average indoors (eg 70 F for 12 hours per day and
60 for the other 12) and a frugal 300 kWh/mo of indoor electrical use
provides 34K Btu of heat on an average day and a 4'x8'x3'-tall EPDM-lined
plywood heat storage tank on the ground containing 4x8x3x62.33 = 5984 pounds
of 140 F water warms the house using an 800 Btu/h-F radiator for 5 cloudy
days until it cools to Tmin and the house thermal conductance is G Btu/h-F
and we keep it 70 F on a 24.4 F morning, (Tmin-70)800 = (70-24.4)G makes
Tmin = 70+0.057G.
On an average day, we need 24(65-31.8)G-34K = 796.8G-34K Btu of heat energy.
If (140-Tmin)5984 = (140-(70+0.057G))5984 Btu = 5d(796.8-34K), G = 136 max,
and Tmin = 78 F, and the house needs 74.4K Btu/day of non-electrical heat.
A 1024 ft^2 house with a 640 ft^2 loft might look like this,
viewed in a fixed font:
an average 31.8 F December day with a 24.4 and 39.2 daily max and min
in Allentown, near the PA Renewable Energy Festival, 9/22-23/07,
http://www.paenergyfest.com, where I'll be talking about the system
below at 2:30 on Saturday and Nathan Hurst will talk about his Mazda
radiator solar heating experiments in Australia at 3:30 on Sunday.
Rich Komp (author of Practical Photovoltaics) will discuss energy-efficient
food storage at 3:30 on Saturday and new PV developments at 4:30 on Sunday.
We will all be exhibiting ourselves and a $35 1995 Mitsubishi 2.0 Eclipse
radiator at an "Ask the Engineer" table near Booth 24 in the exhibit area.
If a house is 65 F on average indoors (eg 70 F for 12 hours per day and
60 for the other 12) and a frugal 300 kWh/mo of indoor electrical use
provides 34K Btu of heat on an average day and a 4'x8'x3'-tall EPDM-lined
plywood heat storage tank on the ground containing 4x8x3x62.33 = 5984 pounds
of 140 F water warms the house using an 800 Btu/h-F radiator for 5 cloudy
days until it cools to Tmin and the house thermal conductance is G Btu/h-F
and we keep it 70 F on a 24.4 F morning, (Tmin-70)800 = (70-24.4)G makes
Tmin = 70+0.057G.
On an average day, we need 24(65-31.8)G-34K = 796.8G-34K Btu of heat energy.
If (140-Tmin)5984 = (140-(70+0.057G))5984 Btu = 5d(796.8-34K), G = 136 max,
and Tmin = 78 F, and the house needs 74.4K Btu/day of non-electrical heat.
A 1024 ft^2 house with a 640 ft^2 loft might look like this,
viewed in a fixed font: