Tam/WB2TT said:
Either, but using 60V is more convenient. P=Vrms**2/R. So for +/- 60 V swing
Vrms =60/SQRT(2) = 42.4V.
Now, for an 8 Ohm load, power will be (42.4 **2) / 8 = 225W. You won't
actually get that much out because the voltage won't quite go to 60 V. 58
might be a reasonable guess.
58V would be pretty good actually. Allowing a Vce of 2V would be reasonable but
there'll be an IR drop in any emitter resistor too. A typical value would be 0.3
ohms and with around 7A peak of load current, you'll lose another 2V there too.
And the really huge variable is power supply regulation. Audio power amps are
not normally operated from regulated supplies. Power supply 'sag' on load of 10V
would be quite normal..
All of the above would bring the full power down to ~ 150W.
Graham