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Active power factor correction

Discussion in 'Electronic Design' started by Scott Ronald, Mar 25, 2008.

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  1. Scott Ronald

    Scott Ronald Guest


    I am simulating an active power factor correction switching regulator.
    I am having a bit of trouble getting a good algorithm going for it though.

    Here is my circuit. The input is rectified AC, 60Hz, ~160V
    vin = 160*|sin(2*pi*60*t)|

    | | | |
    | | | |
    [vin] [contro]-[fet] [cap] [load]
    | | | |
    | | [C_ESR] |
    | | | |

    This is the code I am using to simulate the circuit: (StepSize is 1E-9)

    if (SwitchOn)
    //left half
    inductorCurrent += (vin - inductorESRVoltage) * StepSize /

    inductorESRVoltage = inductorCurrent * inductorESR;

    //right half
    capacitorVoltage += loadCurrent * StepSize / capacitance;
    vout = capacitorVoltage + loadCurrent * capacitorESR;
    loadCurrent = vout / loadResistance;
    capacitorCurrent = loadCurrent;
    inductorCurrent += (vin - inductorESRVoltage) *
    StepSize / inductance;
    if (inductorCurrent < 0)
    inductorCurrent = 0;//diode
    inductorESRVoltage = inductorCurrent * inductorESR + vout;
    capacitorVoltage += (inductorCurrent - loadCurrent) * StepSize /

    loadCurrent = vout / loadResistance;
    vout = capacitorVoltage + loadCurrent * capacitorESR;
    capacitorCurrent = inductorCurrent - loadCurrent;

    The PWM controlling the proportion of time on/off for the Switch in the
    above code is here:

    Microloop()//called at 100kHz
    duty = (desiredVout - vout)*(k * vin - inductorCurrent);
    //the (desiredVout - vout) sets the error for the output voltage
    //(k * vin - inductorCurrent) sets an error current for the input, to
    //make sure the input current is proportional to input voltage. I have
    //been using a k of 0.25
    if (duty >= 95)
    duty = 95;
    else if (duty < 0)
    duty = 0;

    The problem with my simulated controller as it stands is that the
    inductor current has a lot of ripple in it, but the magnitude of the
    inductor ripple is proportional to the input voltage. The output
    voltage regulates well though. Do I need to make changes to my circuit
    or algorithm to make this work better?

  2. MooseFET

    MooseFET Guest

    Note the lack of an input side EMI filter and that the input side
    bridge circuit is modeled.
    This is basically right as a straight line modeling of the switching.
    You can do a bit better if you do one of the summing actions twice per
    loop and divide the amount by two. This helps if you have one short
    time constant and one longer one.

    A lossless diode is hard to find in real life.
    I haven't looked carefully enough but the above looks incorrect to
    me. The servo loop of your PWM circuit needs to be much slower than
    the PWM action and a lot faster than the mains frequency. You seem to
    have it at the PWM frequency.

    The input side ripple at the switching frequency is normal. You can't
    get rid of it in the topology you have. The frequency content below
    that should be just the mains frequency.
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