S
Scott Ronald
- Jan 1, 1970
- 0
legg said:There's a measurement technique suggested by Kwasniok, Bui, Kozlowski
and Stuchly in the IEEE Transactions on EMC Vol35 #1 Feb'93.
RL
Suppose that someone wanted to generate 3kW on the power line the
equation to calculate this power would be
{[(VgeneratorPeak - VlinePeak)/sqrt(2)]^2}/LineImpedence = 3kW
Is this correct?
If the impedence is high then the generator peak voltage must also be
high. Unless you had a way to change your generator peak voltage you
cannot reliably generate 3kW, since you are at the mercy of the local
line impedence.
Scott