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A zener diode question

Discussion in 'Electronics Homework Help' started by Atakan, Feb 27, 2017.

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  1. Atakan

    Atakan

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    Dec 18, 2016
    Who can solve this question and where is zener diode's resistance ?
     

    Attached Files:

  2. AnalogKid

    AnalogKid

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    Jun 10, 2015
    I can.
     
  3. Atakan

    Atakan

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    Dec 18, 2016
    can u explain me how you did? i am needing so.
     
  4. AnalogKid

    AnalogKid

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    Jun 10, 2015
    Since this is a homework problem, first you show us your work. Then we advise.

    ak
     
  5. Atakan

    Atakan

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    Dec 18, 2016
    i did 10-5.6 / 100 = 0.044 A = Iz and then 5.6/220+2.2k= 2.3mA=IL and then already vo=vz namely vo=5.6V is it true ?
     
  6. duke37

    duke37

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    Jan 9, 2011
    Put some brackets in your equations to define what should be calculated first. Thus 10-5.6/100 should read (10-5.6)/100

    44mA is NOT Iz
    5.6/(220+2k2)=2.3mA correct
     
  7. Atakan

    Atakan

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    Dec 18, 2016
    5.6/100= 56mA so that iz=56mA and then il=2.3mA
    if i sketch 100ohm's next to ix , namely, ix=iz+iL =2.3mA+56mA= 58.3mA= ix ?????
    A question, What is A ? a is 0 or other ?
     
  8. duke37

    duke37

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    Jan 9, 2011
    56mA is the current through the 100Ω resistor. This goes two ways, some through the zener and some through the series resistors (2.3mA) so what is left to go through the zener?
     
    CDRIVE likes this.
  9. Atakan

    Atakan

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    Dec 18, 2016
    ix=İz+İL
    ix= (10-5.6)/100=44mA
    il= 5.6/(220+2200)= 2.3mA
    ix-il=iz 44mA-2.3mA= 41.7mA=iz
    is it true?
    And then what is vo?
    Why is there ampermeter? what is value of ampermeter?
     
  10. duke37

    duke37

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    Jan 9, 2011
    The diagram shows Vo=Vz but does not show where the output would be connected.
    The meter is to measure the current through the bypass as the resistor is changed.
     
    Atakan likes this.
  11. Atakan

    Atakan

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    Dec 18, 2016
    thank you for helping , by the way, is my response true? if you say it , i am pleasure.
     
  12. duke37

    duke37

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    Jan 9, 2011
    All seems to be correct, congratulations.
     
    chopnhack likes this.
  13. CDRIVE

    CDRIVE Hauling 10' pipe on a Trek Shift3

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    May 8, 2012
    Trevor, I have to click a "LIke" somewhere in this thread but I'm not settled on which of your replies it will be. You did a great job of walking him through the problem without actually doing the work for him.
    On second thought it's got to be this one because it ends with a "?". It's reminiscent of how shrinks are depicted when the patient asks ..."Doc, do you think that this has anything to do with my problem"? And the $100.00/Hr shrink (who never offers and opinion) invariably replies with ... "What do you think"? :)

    Atakan, fortunate for you that Duke's therapy is free! :D


    Chris
     
    chopnhack likes this.
  14. Petkan

    Petkan

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    Feb 9, 2011
    Atakan:

    Here is a simple approach:
    1. First assume the voltage across the zener is always 5.6V.
    2. Calculate the current through its ballast resistor on the left as I=(Vin-Vz)/R
    3. Calculate the load current as Vz/(Rload) (assuming ideal A meter with zero resistance)
     
    Last edited by a moderator: Mar 4, 2017
  15. duke37

    duke37

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    Jan 9, 2011
    The resistance of a zener diode is used to describe the change in voltage as the current is changed. Often this resistance is taken as zero.
    Free?
    I was hoping for some Turkish delight.:D:D
     
  16. Audioguru

    Audioguru

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    599
    Sep 24, 2016
    I like Afternoon delight!;)
     
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