LED Lumens to Lux conversion?

Discussion in 'Electronic Basics' started by TazaTek, Nov 15, 2007.

  1. TazaTek

    TazaTek Guest

    Hi,

    I'm trying to pick out some LED's for to make a 10,000 Lux @ 36 inches
    (or 1 meter) LED lamp. My problem is that I'm not quite sure of how
    to convert the lumens spec on the LED to the Lux to figure out how
    many LED's I need to buy.

    I know that Lux = Lumens/ m2 , but I'm not exactly sure of how that
    applies to something that is 1 meter away, and would be, say the size
    of a small book.

    I'm currently looking at the Phillips' Luxeon 5 watt stars. Any feed
    back on that as a high output LED?

    Any help would be appreciated.


    Thanks

    Matt
    TazaTek, Nov 15, 2007
    #1
  2. TazaTek

    Nobody Guest

    On Wed, 14 Nov 2007 16:50:37 -0800, TazaTek wrote:

    > I'm trying to pick out some LED's for to make a 10,000 Lux @ 36 inches
    > (or 1 meter) LED lamp. My problem is that I'm not quite sure of how
    > to convert the lumens spec on the LED to the Lux to figure out how
    > many LED's I need to buy.
    >
    > I know that Lux = Lumens/ m2 , but I'm not exactly sure of how that
    > applies to something that is 1 meter away, and would be, say the size
    > of a small book.


    The lux depends upon the size of the spot, and thus the illumination
    angle. A wide-angle LED will produce a lower lux figure for the same
    lumens.

    To determine a rough lux value, divide the lumens figure by the area of
    the LED's "spot". E.g. for even illumination over a 90-degree (+/-
    45-degree) cone at 1 metre, the spot radius will be 1m*45*pi/180 ~=
    785mm, and the area will be ~1.94 square metres, so lux ~= lumens/1.94.

    If the "size of a small book" refers to focusing the entire output of
    the LED on a small area, then the only factor is the area on which you're
    focusing it, not the distance (obviously, you'll need to narrow the angle
    as the distance increases to keep the smaller area).

    E.g. if you're focusing on a 10cm square, lux = lumens / 0.01, so you
    would need 100 lumens to get 10000 lux.
    Nobody, Nov 15, 2007
    #2
  3. TazaTek

    Bob Myers Guest

    "Nobody" <> wrote in message
    news:p...

    > E.g. if you're focusing on a 10cm square, lux = lumens / 0.01, so you
    > would need 100 lumens to get 10000 lux.


    At a bare minimum - we should also note that this would assume
    that every photon made by the light source winds up on that
    10 cm square, which is hardly ever the case. In other words,
    as usual - everything's lossy, and if you don't design in some
    margin you should expect to come up short.

    Bob M.
    Bob Myers, Nov 15, 2007
    #3
  4. TazaTek

    TazaTek Guest

    On Nov 15, 12:49 pm, Nobody <> wrote:
    > On Wed, 14 Nov 2007 16:50:37 -0800, TazaTek wrote:
    > > I'm trying to pick out some LED's for to make a 10,000 Lux @ 36 inches
    > > (or 1 meter) LED lamp. My problem is that I'm not quite sure of how
    > > to convert the lumens spec on the LED to the Lux to figure out how
    > > many LED's I need to buy.

    >
    > > I know that Lux = Lumens/ m2 , but I'm not exactly sure of how that
    > > applies to something that is 1 meter away, and would be, say the size
    > > of a small book.

    >
    > The lux depends upon the size of the spot, and thus the illumination
    > angle. A wide-angle LED will produce a lower lux figure for the same
    > lumens.
    >
    > To determine a rough lux value, divide the lumens figure by the area of
    > the LED's "spot". E.g. for even illumination over a 90-degree (+/-
    > 45-degree) cone at 1 metre, the spot radius will be 1m*45*pi/180 ~=
    > 785mm, and the area will be ~1.94 square metres, so lux ~= lumens/1.94.
    >
    > If the "size of a small book" refers to focusing the entire output of
    > the LED on a small area, then the only factor is the area on which you're
    > focusing it, not the distance (obviously, you'll need to narrow the angle
    > as the distance increases to keep the smaller area).
    >
    > E.g. if you're focusing on a 10cm square, lux = lumens / 0.01, so you
    > would need 100 lumens to get 10000 lux.



    OK. I think I understand. This would apply to the case where we are
    slicing the cone for the whole output angle.
    but how do I calculate the lux for an object that is less than the
    output area?

    for instance, (taking your numbers),
    how would I calculate the lux on an object that has a spot radius of
    only 500mm at 1 meter where the LED has a width pattern of 785mm? This
    would have a portion of the light going past the object on all sides

    Can I *assume* that the light is uniform and therefore just take the
    difference ie. lux = lumens/(1.94 - .785) (if its within a fair
    margin, I'll call it good)

    Thanks

    Matt
    TazaTek, Nov 16, 2007
    #4
  5. TazaTek

    Nobody Guest

    On Fri, 16 Nov 2007 05:25:27 -0800, TazaTek wrote:

    > OK. I think I understand. This would apply to the case where we are
    > slicing the cone for the whole output angle.
    > but how do I calculate the lux for an object that is less than the
    > output area?


    The lux depends upon the area over which the light is spread, regardless
    of what it falls on.

    If you have 10000 lux falling on a sheet of paper, and you replace it with
    a smaller sheet, it's still 10000 lux.

    OTOH, if you narrow the beam to focus the same amount of light on a
    smaller area, the lux goes up.

    > for instance, (taking your numbers),
    > how would I calculate the lux on an object that has a spot radius of
    > only 500mm at 1 meter where the LED has a width pattern of 785mm? This
    > would have a portion of the light going past the object on all sides
    >
    > Can I *assume* that the light is uniform and therefore just take the
    > difference ie. lux = lumens/(1.94 - .785) (if its within a fair
    > margin, I'll call it good)


    No, lux is independent of the size of the target.

    The lumens figure is roughly analogous to watts, except that it's weighted
    according to human visual perception. Similarly, lux = lumens/m^2 is
    analogous to W/m^2. It is an indication of the brightness at a particular
    point. E.g. the brightness of the light from a 40W bulb falling on a sheet
    of paper 1m away is independent of the size of the piece of paper.
    Nobody, Nov 16, 2007
    #5
  6. TazaTek

    TazaTek Guest

    On Nov 16, 8:18 am, Nobody <> wrote:
    > On Fri, 16 Nov 2007 05:25:27 -0800, TazaTek wrote:
    > > OK. I think I understand. This would apply to the case where we are
    > > slicing the cone for the whole output angle.
    > > but how do I calculate the lux for an object that is less than the
    > > output area?

    >
    > The lux depends upon the area over which the light is spread, regardless
    > of what it falls on.
    >
    > If you have 10000 lux falling on a sheet of paper, and you replace it with
    > a smaller sheet, it's still 10000 lux.
    >
    > OTOH, if you narrow the beam to focus the same amount of light on a
    > smaller area, the lux goes up.
    >
    > > for instance, (taking your numbers),
    > > how would I calculate the lux on an object that has a spot radius of
    > > only 500mm at 1 meter where the LED has a width pattern of 785mm? This
    > > would have a portion of the light going past the object on all sides

    >
    > > Can I *assume* that the light is uniform and therefore just take the
    > > difference ie. lux = lumens/(1.94 - .785) (if its within a fair
    > > margin, I'll call it good)

    >
    > No, lux is independent of the size of the target.
    >
    > The lumens figure is roughly analogous to watts, except that it's weighted
    > according to human visual perception. Similarly, lux = lumens/m^2 is
    > analogous to W/m^2. It is an indication of the brightness at a particular
    > point. E.g. the brightness of the light from a 40W bulb falling on a sheet
    > of paper 1m away is independent of the size of the piece of paper.


    Great, I think I get it now....

    Thanks
    matt
    TazaTek, Nov 16, 2007
    #6

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